# Quadratic Equations Watch

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Hi there, I need to understand how you factorise equations like this.. can someone do the solution so I could follow through thank you

2x^2 + 11x + 12

Thank you

2x^2 + 11x + 12

Thank you

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#2

=2x^2 8x 3x 12

=2x (x 4) 3(× 4)

=(2x 3)(x 4)

I hope this can help you to understand

12×2 (1st and last number )=24

24= 2×2×2×3

so u have to make 11 (middle number)

=2x (x 4) 3(× 4)

=(2x 3)(x 4)

I hope this can help you to understand

12×2 (1st and last number )=24

24= 2×2×2×3

so u have to make 11 (middle number)

Last edited by Mehz_19; 1 month ago

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#4

For my A-Level Maths, I was taught a method for factorising quadratic equations; it'll seem complicated but I'll try to make the method as clear as I can.

So, if the equation is 2x² + 11x + 12...

You'll first want to separate the '11x' part into two additions.

To do this, multiply the 2 (the x² coefficient) with the 12 (the constant, without an x) = 24.

Then, see what two numbers

Thus, you write the equation as... 2x² + 8x + 3x + 12

With this new equation (where the x coefficient is merely split into two additions), divide it into two halves and factorise so that there is a common factor of each... 2x² + 8x + 3x + 12 will become... 2x(x + 4) + 3(x + 4)

The (x + 4) is the common factor here, so you can write the factorised equation as (2x + 3)(x + 4).

Yeah, I've explained this really badly and I'm certain that somebody will be able to explain this or another method far better - but oh well, it's one way!

So, if the equation is 2x² + 11x + 12...

You'll first want to separate the '11x' part into two additions.

To do this, multiply the 2 (the x² coefficient) with the 12 (the constant, without an x) = 24.

Then, see what two numbers

**multiply**to get 24, while also that**add**to get 11 (the x coefficient). The two numbers here would be 8 and 3.Thus, you write the equation as... 2x² + 8x + 3x + 12

With this new equation (where the x coefficient is merely split into two additions), divide it into two halves and factorise so that there is a common factor of each... 2x² + 8x + 3x + 12 will become... 2x(x + 4) + 3(x + 4)

The (x + 4) is the common factor here, so you can write the factorised equation as (2x + 3)(x + 4).

Yeah, I've explained this really badly and I'm certain that somebody will be able to explain this or another method far better - but oh well, it's one way!

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(Original post by

=2x^2+8x+3x+12

=2x (x+4)+3(×+4)

=(2x+3)(x+4)

I hope this can help you to understand

12×2 (1st and last number )=24

24= 2×2×2×3

so u have to make +11 (middle number)

so u have to make

24

**Mehz_19**)=2x^2+8x+3x+12

=2x (x+4)+3(×+4)

=(2x+3)(x+4)

I hope this can help you to understand

12×2 (1st and last number )=24

24= 2×2×2×3

so u have to make +11 (middle number)

so u have to make

24

(Original post by

For my A-Level Maths, I was taught a method for factorising quadratic equations; it'll seem complicated but I'll try to make the method as clear as I can.

So, if the equation is 2x² + 11x + 12...

You'll first want to separate the '11x' part into two additions.

To do this, multiply the 2 (the x² coefficient) with the 12 (the constant, without an x) = 24.

Then, see what two numbers

Thus, you write the equation as... 2x² + 8x + 3x + 12

With this new equation (where the x coefficient is merely split into two additions), divide it into two halves and factorise so that there is a common factor of each... 2x² + 8x + 3x + 12 will become... 2x(x + 4) + 3(x + 4)

The (x + 4) is the common factor here, so you can write the factorised equation as (2x + 3)(x + 4).

Yeah, I've explained this really badly and I'm certain that somebody will be able to explain this or another method far better - but oh well, it's one way!

**luke.ah**)For my A-Level Maths, I was taught a method for factorising quadratic equations; it'll seem complicated but I'll try to make the method as clear as I can.

So, if the equation is 2x² + 11x + 12...

You'll first want to separate the '11x' part into two additions.

To do this, multiply the 2 (the x² coefficient) with the 12 (the constant, without an x) = 24.

Then, see what two numbers

**multiply**to get 24, while also that**add**to get 11 (the x coefficient). The two numbers here would be 8 and 3.Thus, you write the equation as... 2x² + 8x + 3x + 12

With this new equation (where the x coefficient is merely split into two additions), divide it into two halves and factorise so that there is a common factor of each... 2x² + 8x + 3x + 12 will become... 2x(x + 4) + 3(x + 4)

The (x + 4) is the common factor here, so you can write the factorised equation as (2x + 3)(x + 4).

Yeah, I've explained this really badly and I'm certain that somebody will be able to explain this or another method far better - but oh well, it's one way!

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#6

(Original post by

Hi there, I need to understand how you factorise equations like this.. can someone do the solution so I could follow through thank you

2x^2 + 11x + 12

Thank you

**MissCarter786**)Hi there, I need to understand how you factorise equations like this.. can someone do the solution so I could follow through thank you

2x^2 + 11x + 12

Thank you

Something you probably learned about half way through the GCSE content.

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