cclara
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Pls pls help with full detailed working

What volume of ammonia gas will be produced in the following reaction if 50 cm3 of 0.5 mol/dm3 sodium hydroxide is boiled with 50 cm3 of 0.4 mol/dm3 ammonium chloride solution?
(Note one of these is in excess)

NaOH (aq)+NH4CI (aq)–> Nacl (aq) +H2O (l) NH3(g)
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No. Of moles of NaOH = 0.5*50/1000=0.025 (in excess)
No. Of moles of NH4Cl=0.4*50/1000=0.02
Volume of gas = 0.02*24000=480 cm3
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