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Can someone explain an experiment to determine the Specific Latent Heat of Vaporisation? Let's say for water.
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#5
(Original post by AlishaWhite)
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#6
specific latent heat is the energy needed to change the state. so use equation Q=ml with l being the specific latent heat of the object. for a experiment you will need to know the amount of energy needed to evaporate a given mass of water ,then rearrange the equation to give Q/m=l which gives the specific latent heat of evaporisation for water
(Original post by AlishaWhite)
Can someone explain an experiment to determine the Specific Latent Heat of Vaporisation? Let's say for water.
Can someone explain an experiment to determine the Specific Latent Heat of Vaporisation? Let's say for water.
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#7
(Original post by yjacobs)
specific latent heat is the energy needed to change the state. so use equation Q=ml with l being the specific latent heat of the object. for a experiment you will need to know the amount of energy needed to evaporate a given mass of water ,then rearrange the equation to give Q/m=l which gives the specific latent heat of evaporisation for water
specific latent heat is the energy needed to change the state. so use equation Q=ml with l being the specific latent heat of the object. for a experiment you will need to know the amount of energy needed to evaporate a given mass of water ,then rearrange the equation to give Q/m=l which gives the specific latent heat of evaporisation for water
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(Original post by neluxsan)
You set an ice in a funnel with a immersion heater, with a beaker underneath (this is the control - like the thing you are using to test against). You set up the same exact thing in another funnel, but this time you connect one to an electric source. You wait till water starts dropping (due to ice melting). As soon as ice starts melting, turn on the immersion heater. Wait for 15 mins so reasonable amount of water can be collected from melting. Measure the mass of water in both beakers and then find the difference. This difference is equal to mass of ice melted due to immersion heater. Use the formula E=mL to find L (specific latent heat).
You set an ice in a funnel with a immersion heater, with a beaker underneath (this is the control - like the thing you are using to test against). You set up the same exact thing in another funnel, but this time you connect one to an electric source. You wait till water starts dropping (due to ice melting). As soon as ice starts melting, turn on the immersion heater. Wait for 15 mins so reasonable amount of water can be collected from melting. Measure the mass of water in both beakers and then find the difference. This difference is equal to mass of ice melted due to immersion heater. Use the formula E=mL to find L (specific latent heat).
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#9
(Original post by AlishaWhite)
Thx. That is for fusion right? What would an experiment for vaporisation be?
Thx. That is for fusion right? What would an experiment for vaporisation be?
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#10
(Original post by AlishaWhite)
Thx. That is for fusion right? What would an experiment for vaporisation be?
Thx. That is for fusion right? What would an experiment for vaporisation be?
For vaporisation, its harder to explain coz idk the equipment names myself... better to look at a picture whilst reading my explaination
You have this spherical container which has gaps to allow gas to flow through, when you heat up water to steam
You have a condenser to cool down the steam and collect it in a beaker
You have an immersion heater fitted inside the spherical container
So you heat up the water and let gas flow into the condenser which cools down and then collects the water.
Energy to heat is calculated via E=I*V*T
Measure mass of water
Use formula E = M*L to find answer
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#11
(Original post by yjacobs)
fusion and evaporisation is the same thing experiment/ constant wise, its just a different state change- i think. also the experiment would be to heat up liquid water until its fully evaporated. then somehow find out how much energy was used and use the equa
fusion and evaporisation is the same thing experiment/ constant wise, its just a different state change- i think. also the experiment would be to heat up liquid water until its fully evaporated. then somehow find out how much energy was used and use the equa
(Original post by neluxsan)
You set an ice in a funnel with a immersion heater, with a beaker underneath (this is the control - like the thing you are using to test against). You set up the same exact thing in another funnel, but this time you connect one to an electric source. You wait till water starts dropping (due to ice melting). As soon as ice starts melting, turn on the immersion heater. Wait for 15 mins so reasonable amount of water can be collected from melting. Measure the mass of water in both beakers and then find the difference. This difference is equal to mass of ice melted due to immersion heater. Use the formula E=mL to find L (specific latent heat).
You set an ice in a funnel with a immersion heater, with a beaker underneath (this is the control - like the thing you are using to test against). You set up the same exact thing in another funnel, but this time you connect one to an electric source. You wait till water starts dropping (due to ice melting). As soon as ice starts melting, turn on the immersion heater. Wait for 15 mins so reasonable amount of water can be collected from melting. Measure the mass of water in both beakers and then find the difference. This difference is equal to mass of ice melted due to immersion heater. Use the formula E=mL to find L (specific latent heat).
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#12
(Original post by yjacobs)
fusion and evaporisation is the same thing experiment/ constant wise, its just a different state change- i think. also the experiment would be to heat up liquid water until its fully evaporated. then somehow find out how much energy was used and use the equation before
fusion and evaporisation is the same thing experiment/ constant wise, its just a different state change- i think. also the experiment would be to heat up liquid water until its fully evaporated. then somehow find out how much energy was used and use the equation before
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#13
(Original post by neluxsan)
Not same experiment because when you use a funnel to heat up the water, it would escape as gas so you wouldn't be able to collect the water(the 'steam') and measure it.
Not same experiment because when you use a funnel to heat up the water, it would escape as gas so you wouldn't be able to collect the water(the 'steam') and measure it.
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(Original post by yjacobs)
in this experiment how do you find out E?
in this experiment how do you find out E?
Energy = power x time
So E = V I t
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(Original post by neluxsan)
Not same experiment because when you use a funnel to heat up the water, it would escape as gas so you wouldn't be able to collect the water(the 'steam') and measure it.
Not same experiment because when you use a funnel to heat up the water, it would escape as gas so you wouldn't be able to collect the water(the 'steam') and measure it.
Then use that mass in E=mL
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#16
(Original post by AlishaWhite)
If you have a powr source u can attatch a voltmeter and ammeter to it and then time using a stopwatch.
Energy = power x time
So E = V I t
If you have a powr source u can attatch a voltmeter and ammeter to it and then time using a stopwatch.
Energy = power x time
So E = V I t
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#18
(Original post by AlishaWhite)
Instead of collecting it, could you not measure change in mass (so mass of water evaporated)??
Then use that mass in E=mL
Instead of collecting it, could you not measure change in mass (so mass of water evaporated)??
Then use that mass in E=mL
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