# Physics Homework help 2 - i accidentally put it under maths

Announcements
#1

During WW1, the German army bombarded Paris with "Big Bertha." Assume Big Bertha fired shells with an initial velocity of 1.1 x 10^3 m/s [ 45 above the horizontal ]
a) how long was each shell airborne, if the launch point was at the same level as the landing point? -answer is 1.6 x 10^2 s
b) Determine the maximum horizontal range of each shell -answer is 1.2 x 10^5 km
c) Determine the maximum height of each shell -answer is 31 km

An astronaut on the Moon where gravity is 1.6 m/s^2 strikes a ball giving it a velocity of 32 m/s [ 35 degrees above the Moon's horizontal ] The ball lands in a crater floor that is 15 m below the level where it was struck. Determine
a) the maximum height of the ball -answer : 1.1 x 10^2 m
b) time of flight -answer is 24s
c) horizontal range -answer is6.2 x 10^2 m
0
2 years ago
#2
(Original post by Jih)

During WW1, the German army bombarded Paris with "Big Bertha." Assume Big Bertha fired shells with an initial velocity of 1.1 x 10^3 m/s [ 45 above the horizontal ]
a) how long was each shell airborne, if the launch point was at the same level as the landing point? -answer is 1.6 x 10^2 s
b) Determine the maximum horizontal range of each shell -answer is 1.2 x 10^5 km
c) Determine the maximum height of each shell -answer is 31 km

An astronaut on the Moon where gravity is 1.6 m/s^2 strikes a ball giving it a velocity of 32 m/s [ 35 degrees above the Moon's horizontal ] The ball lands in a crater floor that is 15 m below the level where it was struck. Determine
a) the maximum height of the ball -answer : 1.1 x 10^2 m
b) time of flight -answer is 24s
c) horizontal range -answer is6.2 x 10^2 m
you will need to break the initial velocity into horizontal and vertical components using trig and then use the SUVAT equations of motion to calculate the answers.

the time of flight for the shell in the first question will be the time taken for a projectile fired vertically with the same velocity as the vertical component of the shells launch velocity to fall back to it's initial position.

the range of the shell will be the horizontal distance travelled in that amount of time calculated above at the horizontal component of initial velocity.
0
X

new posts Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Year 12s - where are you at with making decisions about university?

I’ve chosen my course and my university (10)
35.71%
I’ve chosen my course and shortlisted some universities (9)
32.14%
I’ve chosen my course, but not any universities (2)
7.14%
I’ve chosen my university, but not my course (1)
3.57%
I’ve shortlisted some universities, but not my course (2)
7.14%
I’m starting to consider my university options (3)
10.71%
I haven’t started thinking about university yet (0)
0%
I’m not planning on going to university (1)
3.57%