S.A.M123
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An engine develops 10W of power through what vertical height can it raise a 10kg mass in 5.0s

And also
A train moving at a uniform velocity of 72 km H to the power of -1 as a total frictional force of 200 N acting against it how much work is done in 1 second?

Thank you so much for helping
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Hazelly
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(Original post by S.A.M123)
An engine develops 10W of power through what vertical height can it raise a 10kg mass in 5.0s

And also
A train moving at a uniform velocity of 72 km H to the power of -1 as a total frictional force of 200 N acting against it how much work is done in 1 second?

Thank you so much for helping
Hello,

What working out have you done so far? Have you thought about the possible formulas you may need to use?
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RogerOxon
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(Original post by S.A.M123)
An engine develops 10W of power through what vertical height can it raise a 10kg mass in 5.0s

And also
A train moving at a uniform velocity of 72 km H to the power of -1 as a total frictional force of 200 N acting against it how much work is done in 1 second?
The basic principle here is that the work done by a force is equal to its magnitude multiplied by the distance through which it moves, in its direction. In both of these questions the force and the distance through which it moves are in the same direction, so it's just the magnitude of the force multiplied by the distance it moves.

1. The engine has a power of 10W = 10 Js^{-1}. How much work does it do in 5s? To raise the mass at a constant rate, you need to apply a force equal and opposite to its weight. What is its weight? How far can that force be moved with the energy expended by the engine in 5s?

2. How far does the train move in 1s? How much work is therefore done by the force overcoming friction?
Last edited by RogerOxon; 5 months ago
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S.A.M123
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I don’t understand how to do the first one I just got confused
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