# A level further maths help needed!

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#1
Use sigma notation to write these sums
1^5+2^5+3^5...n^5

Could someone give me some insight on how to do this?
0
1 year ago
#2
(Original post by Juliakinga)
Use sigma notation to write these sums
1^5+2^5+3^5...n^5

Could someone give me some insight on how to do this?
Are you able to identify what the general term of this series is? Let's say it's the th term, then what is it in terms of r ??
0
1 year ago
#3
(Original post by Juliakinga)
Use sigma notation to write these sums
1^5+2^5+3^5...n^5

Could someone give me some insight on how to do this?
What is the general term with r as a veriable?

Then Sigma of that for r = 1 to r = n
0
1 year ago
#4
(Original post by Juliakinga)
Use sigma notation to write these sums
1^5+2^5+3^5...n^5

Could someone give me some insight on how to do this?
What's the same in each term? ^5
What's changing? The base number 1, 2, 3, ..., n.
Let's use i to represent the base number (could use any letter).
So in the first term i = 1 and in the second term i = 2 and so on up to the last term where i = n.
So it's the sum (sigma) of i^5 with i going from 1 to n.
0
#5
(Original post by RDKGames)
Are you able to identify what the general term of this series is? Let's say it's the th term, then what is it in terms of r ??
Would it be the power of 5
0
#6
(Original post by Muttley79)
What is the general term with r as a veriable?

Then Sigma of that for r = 1 to r = n
So the general term is 5 so I would write it as n to the power of 5?
0
#7
(Original post by MarkFromWales)
What's the same in each term? ^5
What's changing? The base number 1, 2, 3, ..., n.
Let's use i to represent the base number (could use any letter).
So in the first term i = 1 and in the second term i = 2 and so on up to the last term where i = n.
So it's the sum (sigma) of i^5 with i going from 1 to n.
Ahhh okay thank you!!
0
1 year ago
#8
(Original post by Juliakinga)
So the general term is 5 so I would write it as n to the power of 5?
Depends what you are going to use on the sigma - you were given a general term so use that by as r^5 then put r = 1 to n
0
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