# A level further maths help needed!

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How many terms are there in the series

3n sigma 1 (r^2-r+3)

- would it be 3?

B) write and simplify the (2n+1)th term and find the sum of the series

A) 1+2+3+...+3n

Would really appreciate any hell

3n sigma 1 (r^2-r+3)

- would it be 3?

B) write and simplify the (2n+1)th term and find the sum of the series

A) 1+2+3+...+3n

Would really appreciate any hell

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#2

(Original post by

How many terms are there in the series

3n sigma 1 (r^2-r+3)

- would it be 3?

B) write and simplify the (2n+1)th term and find the sum of the series

A) 1+2+3+...+3n

Would really appreciate any hell

**Juliakinga**)How many terms are there in the series

3n sigma 1 (r^2-r+3)

- would it be 3?

B) write and simplify the (2n+1)th term and find the sum of the series

A) 1+2+3+...+3n

Would really appreciate any hell

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#4

**Juliakinga**)

How many terms are there in the series

3n sigma 1 (r^2-r+3)

- would it be 3?

B) write and simplify the (2n+1)th term and find the sum of the series

A) 1+2+3+...+3n

Would really appreciate any hell

For (B), if the

**r**th term is , then the

**(2n+1)**th term is ... ???

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(Original post by

Not quite. If I pick n=2 then what's the upper limit? Hence how many terms are you adding in this sum?? So what's the number of terms in terms of n???

For (B), if the

**RDKGames**)Not quite. If I pick n=2 then what's the upper limit? Hence how many terms are you adding in this sum?? So what's the number of terms in terms of n???

For (B), if the

**r**th term is , then the**(2n+1)**th term is ... ???And would you put (2n+1) into the equation?

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#6

(Original post by

I have no idea what the upper limit is

**Juliakinga**)I have no idea what the upper limit is

So for a general upper limit 3n and lower limit 1, how many terms do we have ??

And would you put (2n+1) into the equation?

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(Original post by

Come on now, the upper limit is 3n. If I pick n=2 then this just becomes 6. Since the lower limit is always 1, you will have exactly 6 terms.

So for a general upper limit 3n and lower limit 1, how many terms do we have ??

Simple as that.

**RDKGames**)Come on now, the upper limit is 3n. If I pick n=2 then this just becomes 6. Since the lower limit is always 1, you will have exactly 6 terms.

So for a general upper limit 3n and lower limit 1, how many terms do we have ??

Simple as that.

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#8

(Original post by

So we would have up to 9 terms? I’m sorry I’m really bad at wordy things

**Juliakinga**)So we would have up to 9 terms? I’m sorry I’m really bad at wordy things

I suggest you go back to the basics of how sigma notation works to ensure you understand why.

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(Original post by

The sum will have exactly terms.

I suggest you go back to the basics of how sigma notation works to ensure you understand why.

**RDKGames**)The sum will have exactly terms.

I suggest you go back to the basics of how sigma notation works to ensure you understand why.

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