C3 Functions helpWatch

#1
1d) Given that what is:

i)

ii) (thats the inverse of the (fg) function by the way)

I got i) as being
Is that right?

And i don't understand part ii).. any help would be appreciated!

Oh, and i know about how to get inverse functions.. but i dont know how to do it at all on this question
0
10 years ago
#2
, which is a result you should know and can quote. It's composed as a normal function is, so .
0
10 years ago
#3
First part is right, yeah. For part two, the notation seems to be a bit off... do you mean fg^-1(x)=-6?

edit: Nevermind. Genius above beat me to it.
0
#4
Ok, great. I'm still a little bit confused tbh though.

So after i've got

and

then which doesnt work, as you can't get the cube root of -8.

Where have i gone wrong?

Sigh, this is what you get when you aren't given a textbook yet, and the library doesn't have any
0
10 years ago
#5
You would get = and putting x=-6 indeed gives a non-real answer... I don't see any mistake
0
10 years ago
#6
(Original post by becky.fm)
then which doesnt work, as you can't get the cube root of -8.
(Original post by nota bene)
You would get = and putting x=-6 indeed gives a non-real answer... I don't see any mistake
Ahem... the cube root of -8 is -2.
0
#7
(Original post by generalebriety)
Ahem... the cube root of -8 is -2.
Oh ****, yeah Ok, great, done it Thanks!
0
10 years ago
#8
(Original post by becky.fm)
Oh ****, yeah Ok, great, done it Thanks!
No problem.
0
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