# Normal distribution help???

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#1
guyss im really don't understand this question.. i know it is normal distribution but how can I do this?

'The height of door frames used by a building firm in a new apartment complex is 1.830m, however the heights of men are normal distributed with mean 1.730 m and variance of 0.064m^2. Find the proportion of men who will struggle to walk through the door frame?'
0
11 months ago
#2
(Original post by myii)
guyss im really don't understand this question.. i know it is normal distribution but how can I do this?

'The height of door frames used by a building firm in a new apartment complex is 1.830m, however the heights of men are normal distributed with mean 1.730 m and variance of 0.064m^2. Find the proportion of men who will struggle to walk through the door frame?'
Use the cumulative distribution table (z) to find
p(x>1.83)
0
11 months ago
#3
(Original post by myii)
guyss im really don't understand this question.. i know it is normal distribution but how can I do this?

'The height of door frames used by a building firm in a new apartment complex is 1.830m, however the heights of men are normal distributed with mean 1.730 m and variance of 0.064m^2. Find the proportion of men who will struggle to walk through the door frame?'
A normal distribution should be in the form X~N(mean,variance)
The normal distribution of men is X~N(1.73,0.064)
So you want to find the proportion of men that exceed the height of the door
So you want P(X>1.83)
Using your calculator and use normal cd.
For each entry:
Lower Bound:1.83
Upper Bound 123456789 (any large number)
standard deviation (σ) root(0.064) as standard deviation squared is variance
mean (µ) as 1.73
This will find the proportion of men that cant fit

Hope this helps
0
#4
(Original post by Chakram)
A normal distribution should be in the form X~N(mean,variance)
The normal distribution of men is X~N(1.73,0.064)
So you want to find the proportion of men that exceed the height of the door
So you want P(X>1.83)
Using your calculator and use normal cd.
For each entry:
Lower Bound:1.83
Upper Bound 123456789 (any large number)
standard deviation (σ) root(0.064) as standard deviation squared is variance
mean (µ) as 1.73
This will find the proportion of men that cant fit

Hope this helps
I got 0.40? is that correct?
0
11 months ago
#5
(Original post by myii)
I got 0.40? is that correct?
Hi,
I got an answer of 0.346
0
11 months ago
#6
(Original post by myii)
I got 0.40? is that correct?
0
X

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