Jessica_rica
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I get how part A) of this qs but I’m a bit confused with question B)
A) express sinx-root3x in form Rsin(x-a), with R>0 and 0<a<90
B)Hence sketch the graph of y=sinx-rootcosx for -360£<x£<360

From part A) I get the equation y=2sin(x-60) and I can sketch it but I don’t get why the domain still remains -360 and 360 when y=sinx is translated by 60 to the right, in the mark scheme. Wouldn’t it be -300£<x£<420 ???
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old_engineer
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The domain of sin(x) extends from minus infinity degrees to plus infinity degrees. Likewise the domain of Rsin(x - a). They're just asking you to sketch the graph of Rsin(x - a) from x = -360 to x = +360.
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