Aryanajigar
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What mass of magnesium bromide is formed when 1g of magnesium reacts with 5g of bromine?
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Academicbee123
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Is one in excess?
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Adambrl
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Hi again!

when you're given information about multiple reactants, you firstly need to find out which one is the LR to go on and answer the question.

very first thing is to write out a balanced equation for the reaction:

Mg + Br2 --> MgBr2

now work out the number of moles of Mg and Br2

n(Mg) = 1/24.3 = 0.0412 mol
n(Br2) = 5/159.8 = 0.0313 mol

find the reaction ratios from the equation:

Mg:Br2 = 1:1

normally you'd then divide the moles by the respective ratio value, but since it's in a 1:1 ratio you already know that the smallest value will be the one to run out first which In this case, the LR is Br2.

Use the Molar value of Br2 and the Mr of MgBr2 to find the maximum mass of MgBr2 that can be produced:

0.0313 x 184.1 = 5.76 grams. however this answer is probably 1/2 grams +/- since I rounded off my molar values..
Last edited by Adambrl; 1 week ago
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Aryanajigar
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Thank you again! And the answer is 5.76g so you were right
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