# Alevel maths questionWatch

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#1
I get how to find the domain of this question but I’m confused with finding the range
Qs) X=1/3sint , y=sin3t , 0<t<p/2
Which gives me Cartesian y=9x(1-12x^2).
At y=sin3t, 0<t<p/2
Would give me a range of 0<y<1
I don’t get how the solutions gives -1<y£<1
0
4 weeks ago
#2
(Original post by Jessica_rica)
I get how to find the domain of this question but I’m confused with finding the range
Qs) X=1/3sint , y=sin3t , 0<t<p/2
Which gives me Cartesian y=9x(1-12x^2).
At y=sin3t, 0<t<p/2
Would give me a range of 0<y<1
I don’t get how the solutions gives -1<y£<1
y(pi/2) = sin(3pi/2) = -1.
0
#3
(Original post by mqb2766)
y(pi/2) = sin(3pi/2) = -1.
Thanks
0
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