Jessica_rica
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Report Thread starter 4 weeks ago
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I get how to find the domain of this question but I’m confused with finding the range
Qs) X=1/3sint , y=sin3t , 0<t<p/2
Which gives me Cartesian y=9x(1-12x^2).
At y=sin3t, 0<t<p/2
Would give me a range of 0<y<1
I don’t get how the solutions gives -1<y£<1
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mqb2766
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Report 4 weeks ago
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(Original post by Jessica_rica)
I get how to find the domain of this question but I’m confused with finding the range
Qs) X=1/3sint , y=sin3t , 0<t<p/2
Which gives me Cartesian y=9x(1-12x^2).
At y=sin3t, 0<t<p/2
Would give me a range of 0<y<1
I don’t get how the solutions gives -1<y£<1
y(pi/2) = sin(3pi/2) = -1.
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Jessica_rica
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Report Thread starter 4 weeks ago
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(Original post by mqb2766)
y(pi/2) = sin(3pi/2) = -1.
Thanks
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