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If I have the equation y = -10 cos(-8[x-6])
And I have to work out amplitude, period and phase shift
For amplitude 10
Period I'm a bit unsure, I did -8 x 1 which is -8 (as there is a 1 in front of the x) and so it's - 2Pi/8 which is - Pi/4 is this correct?
And I have to work out amplitude, period and phase shift
For amplitude 10
Period I'm a bit unsure, I did -8 x 1 which is -8 (as there is a 1 in front of the x) and so it's - 2Pi/8 which is - Pi/4 is this correct?
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#2
(Original post by Helloaaa)
For amplitude 10
Period I'm a bit unsure, I did -8 x 1 which is -8 (as there is a 1 in front of the x) and so it's - 2Pi/8 which is - Pi/4 is this correct?
For amplitude 10
Period I'm a bit unsure, I did -8 x 1 which is -8 (as there is a 1 in front of the x) and so it's - 2Pi/8 which is - Pi/4 is this correct?
Last edited by MarkFromWales; 2 weeks ago
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(Original post by MarkFromWales)
Yes, it's correct except a period is a positive quantity (time between repeats) so a negative answer doesn't make sense, so pi/4.
Yes, it's correct except a period is a positive quantity (time between repeats) so a negative answer doesn't make sense, so pi/4.
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#4
(Original post by Helloaaa)
Oh yes!! Thanks for pointing that out. How about for the phase shift we wouldn't have to multiply the brackets out for that right? So it would be x-6=0 so phase shift is 6 is that correct?
Oh yes!! Thanks for pointing that out. How about for the phase shift we wouldn't have to multiply the brackets out for that right? So it would be x-6=0 so phase shift is 6 is that correct?

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Would the sum be 3 sin(x) + -9 sin(x) so the answer is -6?
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#6
(Original post by Helloaaa)
If I have Y1 (x) = 3 sin (x) and y2 (x) = -9 sin (x)
Would the sum be 3 sin(x) + -9 sin(x) so the answer is -6?
If I have Y1 (x) = 3 sin (x) and y2 (x) = -9 sin (x)
Would the sum be 3 sin(x) + -9 sin(x) so the answer is -6?
(the amplitude of that is 6)
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