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Unique ID of submitted data on Wireshark

Does anyone know how to find the unique ID of submitted data in Wireshark, or could point me in the direction of where I could find out? I have tried searching online for the answer but couldn’t find one.
What do you mean by 'submitted data'? and what do you mean by 'unique ID'? are you talking about IP packets and the Identification field in the packet header for identifying packet fragments? (i.e. https://tools.ietf.org/html/rfc6864 / https://ccie-or-null.net/2014/12/02/wireshark-tid-bit-what-does-the-ip-identification-field-tell-us/ )

There's a guide to adding columns into wireshark here anyway, the IP identification field should be in that list somewhere: https://unit42.paloaltonetworks.com/unit42-customizing-wireshark-changing-column-display/


Otherwise, I don't know of any protocols which have a field called 'Unique ID', and wireshark won't be able to read protocols that it doesn't know about.
(edited 4 years ago)
Original post by winterscoming
What do you mean by 'submitted data'? and what do you mean by 'unique ID'? are you talking about IP packets and the Identification field in the packet header for identifying packet fragments? (i.e. https://tools.ietf.org/html/rfc6864 / https://ccie-or-null.net/2014/12/02/wireshark-tid-bit-what-does-the-ip-identification-field-tell-us/ )

There's a guide to adding columns into wireshark here anyway, the IP identification field should be in that list somewhere: https://unit42.paloaltonetworks.com/unit42-customizing-wireshark-changing-column-display/


Otherwise, I don't know of any protocols which have a field called 'Unique ID', and wireshark won't be able to read protocols that it doesn't know about.

It wasn't the identification field, so am unsure what the question that I am answering means by 'unique ID'. The submitted data refers to the packets. Thanks for trying
Original post by Anonymous_Cypher
It wasn't the identification field, so am unsure what the question that I am answering means by 'unique ID'. The submitted data refers to the packets. Thanks for trying

Does the question have any more information? like an example of the data/payload in those packets and the protocol? For example, it could be an HTTP packet containing some JSON data containing a field called unique ID (that'd be quite common for something like a browser and web API sending/receiving messages). An example would probably be really useful.
nvm solved it
How? Could you give us a hint?
Reply 6
Original post by Anonymous_Cypher
nvm solved it

Is the answer in the same packet as the flag?
it was a number in the info column. Hopefully this saves you some time.

If anyone can give me any hints for compromised host then it would be appreciated (not the answer, just guidance)
(edited 4 years ago)
Reply 8
Original post by Anonymous_Cypher
it was a number in the info column. Hopefully this saves you some time.

If anyone can give me any hints for compromised host then it would be appreciated (not the answer, just guidance)

What question are you stuck on?
Original post by n3m0byte
What question are you stuck on?

All of it. Any pointers on how to start would be appreciated
Original post by Anonymous_Cypher
All of it. Any pointers on how to start would be appreciated

If you can share the question text (and possibly link to the pcap), I’m sure some of us can help set you in the right direction.
Got it. Thanks though.
(edited 4 years ago)
Original post by Anonymous_Cypher
I have been given a windows virtual machine and I have to answer this question:
The malware persists through reboots. What is the registry key value’s name that results in the malware executing automatically?
This is all I have been given

Once I get this, I should get the gist and be able to find the other answers.

This is one of those questions that a bit of googling can solve (even if you're not well exposed to Windows).

https://docs.microsoft.com/en-us/windows/win32/setupapi/run-and-runonce-registry-keys

should help you along the right path.

(You can try it on your own PC - have it run notepad on startup or something! :smile:)

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