Jessica_rica
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Can someone please help with part c) I don’t get how to find the vertical distance of 2970m
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Microcosm
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(Original post by Jessica_rica)
Can someone please help with part c) I don’t get how to find the vertical distance of 2970m
do you have a copy of the question?
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Jessica_rica
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(Original post by Jessica_rica)
Can someone please help with part c) I don’t get how to find the vertical distance of 2970m
This is the qs
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Jessica_rica
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(Original post by Microcosm)
do you have a copy of the question?
Just posted it
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Microcosm
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(Original post by Jessica_rica)
Just posted it
yeah, just saw it
i think you just substitute whatever value of k you got in part b into the equation for y, because that will give you the total distance travelled by the plane
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baeoftae
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(Original post by Jessica_rica)
Just posted it
is this pure maths 3 or 4
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Jessica_rica
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(Original post by baeoftae)
is this pure maths 3 or 4
Pure maths year 2
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Jessica_rica
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(Original post by Microcosm)
yeah, just saw it
i think you just substitute whatever value of k you got in part b into the equation for y, because that will give you the total distance travelled by the plane
Yeah I did that, as t=99 but that gives me 3000-30(99) = 30
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Bogelles
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All I'm gonna say is there are solution banks for them books online if you search for Edexcel a level maths solution bank, has full workings for every question in the books. Its a good way to understand where you are going wrong
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the bear
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the distance will be the hypotenuse length using the vertical distance y and the horizontal distance x as the two shorter sides of the right angled triangle ?
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mnot
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(Original post by Jessica_rica)
Can someone please help with part c) I don’t get how to find the vertical distance of 2970m
O i think its unclear does it mean horizontal or total ie either way
calculate time between start & ground, Use your time result to calculate distance horizontal & vertical, then use paethagerous to find total distance (we can do this as it says its descent is a straight line...)
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mnot
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(Original post by the bear)
the distance will be the hypotenuse length using the vertical distance y and the horizontal distance x as the two shorter sides of the right angled triangle ?
Yep that was my thinking as to why they specified it took a straight line decent imo
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Microcosm
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(Original post by Jessica_rica)
Yeah I did that, as t=99 but that gives me 3000-30(99) = 30
yes, but y=30 is its position at t=99. you can find the plane's initial position by substituting t=0 and then finding the difference to give the distance travelled.
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