# Binomial distribution

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#2

(Original post by

guyss how can I approach this question?

'A Binomial process over 20 trials with a ﬁxed probability p has a probability of ten successes being 0.0543 and ﬁfteen successes being 0.1457. Find the probability of one trial p??'

**myii**)guyss how can I approach this question?

'A Binomial process over 20 trials with a ﬁxed probability p has a probability of ten successes being 0.0543 and ﬁfteen successes being 0.1457. Find the probability of one trial p??'

You can solve this equation for two values of , but only one of them will fit the second condition you must have:

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(Original post by

You can solve this equation for two values of , but only one of them will fit the second condition you must have:

**RDKGames**)You can solve this equation for two values of , but only one of them will fit the second condition you must have:

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#4

(Original post by

Ahhhh okay, i understand hence do I used both equations and solve for p?

**myii**)Ahhhh okay, i understand hence do I used both equations and solve for p?

What I am suggesting is just using the first one to solve for two value of p, and then just check which one fits the second equation without solving it.

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(Original post by

You can use both simultaneously if you want...

What I am suggesting is just using the first one to solve for two value of p, and then just check which one fits the second equation without solving it.

**RDKGames**)You can use both simultaneously if you want...

What I am suggesting is just using the first one to solve for two value of p, and then just check which one fits the second equation without solving it.

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**RDKGames**)

You can use both simultaneously if you want...

What I am suggesting is just using the first one to solve for two value of p, and then just check which one fits the second equation without solving it.

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#7

(Original post by

so basically do i need to rearrange the first one in the form of p = something?

**myii**)so basically do i need to rearrange the first one in the form of p = something?

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**RDKGames**)

You can use both simultaneously if you want...

What I am suggesting is just using the first one to solve for two value of p, and then just check which one fits the second equation without solving it.

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(Original post by

Basically yeah you do

**Dina_acqua16**)Basically yeah you do

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#10

(Original post by

yeahh i got 0.2? do you think this is correct?

**myii**)yeahh i got 0.2? do you think this is correct?

Look;

is precisely just .

Use this in the equation, we get that

and just solve this quadratic for two values of p?

Last edited by RDKGames; 8 months ago

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#11

You can easily check, by subbing back in the equations.

Why not post your working / validation?

Why not post your working / validation?

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(Original post by

Clearly not. Sub it into the original eqn. to check.

Look;

is precisely just .

Use this in the equation, we get that

and just solve this quadratic for two values of p?

**RDKGames**)Clearly not. Sub it into the original eqn. to check.

Look;

is precisely just .

Use this in the equation, we get that

and just solve this quadratic for two values of p?

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#13

(Original post by

ahhh okay i got 1/2 - 1/root of 5 or 1/2 + 1/root of 5?

**myii**)ahhh okay i got 1/2 - 1/root of 5 or 1/2 + 1/root of 5?

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(Original post by

Again, check it? But not right ...

**mqb2766**)Again, check it? But not right ...

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#15

(Original post by

ahhhh i got 0.997281.. and 2.7180..x10^-3?

**myii**)ahhhh i got 0.997281.. and 2.7180..x10^-3?

Post some working?

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also lol my working is so messy but i will post it when i get some sort of close answer

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#17

(Original post by

well im checking my workings into the second condition of P(X=15) but i don't think im getting the correct p values when i solve the quadratic, i can use the quadratic formula right? Also, you know 10!10! is it 10! times 10!?

also lol my working is so messy but i will post it when i get some sort of close answer

**myii**)well im checking my workings into the second condition of P(X=15) but i don't think im getting the correct p values when i solve the quadratic, i can use the quadratic formula right? Also, you know 10!10! is it 10! times 10!?

also lol my working is so messy but i will post it when i get some sort of close answer

Edit - yes, you can use the quadratic formula, but you can see the answer directly. Yes 10!10! is 10!*10! - you must know this to form the quadratic?

Last edited by mqb2766; 8 months ago

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#18

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(Original post by

The value on the right hand side as you go from line 1 to line 2 is wrong. You seem to be dividing by 10? Can you break up the steps?

**mqb2766**)The value on the right hand side as you go from line 1 to line 2 is wrong. You seem to be dividing by 10? Can you break up the steps?

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#20

(Original post by

which value is it the values in the quadratic formula equation?

**myii**)which value is it the values in the quadratic formula equation?

What is the numerical value of the right hand side?

(0.0543*10!*10!/20!)^(1/10)

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