Maths A level projectile question help!

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#1
I'm stuck on part 1. of the question. I looked at the mark scheme and it says the initial velocity is P. I am a bit confused as to why it is not Pcosα. Please could someone help me understand this question.
Last edited by username4506446; 1 year ago
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1 year ago
#2
(Original post by Anonymous_4657)
I'm stuck on part 1. of the question. I looked at the mark scheme and it says the initial velocity is P. I am a bit confused as to why it is not Pcosα. Please could someone help me understand this question.
If the initial velocity were v in the direction that the projectile is moving, then yes, the initial horizontal velocity would be v cos(α). But the initial velocity is pi + qj, which means that the horizontal component of the velocity (the bit in the i direction) is p and the vertical component of the velocity (the bit in the j direction( is q.
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1 year ago
#3
Since its a vector, you don't need to apply sin or cos when resolving the forces
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#4
(Original post by ApexCoder)
Since its a vector, you don't need to apply sin or cos when resolving the forces
Thanks. How come? it it just a rule that I have got to learn?
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1 year ago
#5
(Original post by Anonymous_4657)
Thanks. How come? it it just a rule that I have got to learn?
Answer this question for me, why do you use sin or cos in the first place
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#6
(Original post by ApexCoder)
Answer this question for me, why do you use sin or cos in the first place
Don’t you draw a triangle and resolve forces? Maybe I’m wrong
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1 year ago
#7
(Original post by Anonymous_4657)
Don’t you draw a triangle and resolve forces? Maybe I’m wrong
Basically, you use either sin or cos, to find the vertical or horizontal magnitude of a force
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1 year ago
#8
You are resolving vertically and you are already given a vertical magnitude of the velocity (or the vertical component of the velocity) by the j-component of the velocity vector.

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Sometimes for a vector (a force, a velocity, impulse etc.), the direction of it given to you may not be acting along the direction you are resolving in.

This is why when finding a vector's effect (in the direction you are resolving in), you have to use sin or cos.
Last edited by simon0; 1 year ago
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1 year ago
#9
(Original post by Anonymous_4657)
it it just a rule that I have got to learn?
No. You need to understand why, then you have nothing to learn.
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