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Maths - Mechanics

A skydiver leapt from a plane. Her descent is modelled as spending the first 45 seconds in
free fall, then immediately deploying her parachute, descending to the ground at a steady
speed of 8ms-1
for 3 minutes.
a) Draw a velocity-time graph for her descent.
b) Draw a distance-time graph for her descent.
c) Draw an acceleration-time graph for her descent.
d) Calculate the total distance of the descent in metres given by this model.
e) Comment on how realistic the model is.
Think of forces (and resultant force). If there is resultant force there is acceleration.
Original post by Student339
A skydiver leapt from a plane. Her descent is modelled as spending the first 45 seconds in
free fall, then immediately deploying her parachute, descending to the ground at a steady
speed of 8ms-1
for 3 minutes.
a) Draw a velocity-time graph for her descent.
b) Draw a distance-time graph for her descent.
c) Draw an acceleration-time graph for her descent.
d) Calculate the total distance of the descent in metres given by this model.
e) Comment on how realistic the model is.

Post what you've done so far ...
Reply 3
Original post by Muttley79
Post what you've done so far ...

Not much. I know that the acceleration of the free fall is just gravity (9.8m/s^2) but I don't know what to work out the velocity
Original post by Student339
Not much. I know that the acceleration of the free fall is just gravity (9.8m/s^2) but I don't know what to work out the velocity

Initial velocity?
What is the gradient of the vel-time graph?
Reply 5
Original post by Muttley79
Initial velocity?
What is the gradient of the vel-time graph?


I really don't know. I haven't done the graph yet
Original post by Student339
I really don't know. I haven't done the graph yet

You need this to draw the graph - it was a hint.
Reply 7
Original post by Muttley79
You need this to draw the graph - it was a hint

So would the acceleration at the start be 9.8?
Original post by Student339
So would the acceleration at the start be 9.8?


Yes, it's falling under gravity at the beginning.
Reply 9
u can use SUVAT equations?
s=ut 1/2at^2
should work I think
(edited 4 years ago)
s=ut+ 1/2at^2
Reply 11
Got it thanks

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