so keep dividing 1,000,000 by 2 until you get to 125,000 i think, so that would be 3, therefore 3 half lives. So if one half life is 5,700 i think you would just multiply that by 3 to get 17100 years. might be wrong.
so keep dividing 1,000,000 by 2 until you get to 125,000 i think, so that would be 3, therefore 3 half lives. So if one half life is 5,700 i think you would just multiply that by 3 to get 17100 years. might be wrong.
so keep dividing 1,000,000 by 2 until you get to 125,000 i think, so that would be 3, therefore 3 half lives. So if one half life is 5,700 i think you would just multiply that by 3 to get 17100 years. might be wrong.
would it not be 8 half lives? 1000000/8 = 125000 then you would do 8 times 5700? 45600? Not sure tho
would it not be 8 half lives? 1000000/8 = 125000 then you would do 8 times 5700? 45600? Not sure tho
No, that would suggest that after 9 half-lives the radioactivity is completely gone, which cannot be the case. The half-life is defined as the time taken for the activity of a radioactive substance to halve. This is constant no matter how much of it was there to begin with. Radioactivity is an exponential decay because the number of decays occurring per second is proportional to how many nucleons there are of it. So after 1 half-life, it's down to 500,000. Then another half-life passes and it's down to 250,000. Then another half-life passes and it's down to 125,000. So with n half-lives that pass, the number of radioactive nuclei is multiplied by (0.5)n
Just as an extra bit: You could generalise this as number of remaining nucleons N(t)=N0(21)n where n is the number of half-lives that have passed and N0 is how many there were to begin with. If you don't have an integer number of half-lives then you'd have to fiddle with logarithms but this only matters in A-level physics.