As chemistry

Which molecule has no loan pairs?

A. BeCl2
B. CF4
C. NH3
D. BH3

The answer is D. I understand that BH3 has no loan pairs, but doesn’t CH4 also have no loan pairs?

(edited 4 years ago)

Reply 1

Munrhe

Original post by Anonymous__02

Which molecule has no loan pairs?

A. BeCl2
B. CF4
C. NH3
D. BH3

The answer is D. I understand that BH3 has no loan pairs, but doesn’t CH4 also have no loan pairs? And I’m guessing A isn’t even an option because it’s an ionic compound

Hi. Could you check your question as I agree, CH4 does not have any lone (not loan) pairs. BeCl2 is not an option as it is linear planar and both electron pairs are bonded so no lone pair or elctrons

Reply 2

Munrhe

Original post by Anonymous__02

Hi. Could you check your question as I agree, CH4 does not have any lone (not loan) pairs. BeCl2 is not an option as it is linear planar and both electron pairs are bonded so no lone pair of electrons

Reply 3

Ben878

It's CF4, not CH4 - the 4 carbon e's bond with all the fluorines

(edited 4 years ago)

Reply 4

Munrhe

Original post by Ben878

It's CF4, not CH4 - there are lone pairs on the fluorine atoms since they have 7 e's and only 1 is used to bond with the carbon

Agreed, his text said CH4 but his Q had CF4 thus the suggestion to check

Reply 5

username4966870

Original post by Ben878

It's CF4, not CH4 - there are lone pairs on the fluorine atoms since they have 7 e's and only 1 is used to bond with the carbon

Wait sorry can you just elaborate further

Reply 6

username4966870

Original post by Munrhe

Agreed, his text said CH4 but his Q had CF4 thus the suggestion to check

Yeah my mistake

Reply 7

Ben878

Original post by Anonymous__02

Wait sorry can you just elaborate further

I assumed (like Munrhe said) it should've been CF4 instead of CH4. If you make a dot and cross diagram for CF4 you will see what I mean

Reply 8

username4966870

Original post by Ben878

I assumed (like Munrhe said) it should've been CF4 instead of CH4. If you make a dot and cross diagram for CF4 you will see what I mean

Oh right . I think I’ve been doing ch4 this whole time without even realising lol

Reply 9

username4966870

Original post by Munrhe

BeCl2 is not an option as it is linear planar and both electron pairs are bonded so no lone pair or elctrons

Sorry do you mean BeCl2 does contain lone pairs?

Reply 10

Ben878

Original post by Anonymous__02

Oh right . I think I’ve been doing ch4 this whole time without even realising lol

Did you check what option B was? I should have been more clear and said although it's CF4, it would not actually make a difference as neither CH4 or CF4 contain lone pairs

And BeCl2 does not contain lone pairs