Motion under gravity Watch

njr008
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Report Thread starter 10 years ago
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I am doing 2nd Year maths and I am having problems trying to work out this question. Any help would be so appreciated!!
If a falling object passes a 2m hight window in 1/10 of a second, how high above the sill was the body at the start of its descent.
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j_jordan
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2.053 M
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j_jordan
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Freefall from top of wndow to bottom:
a=9.8, x=2, t=0.1 u=?

U = X -at = 1.02

Free fall frm start to top of wndow:
u=0, a=9.8, v=1.02, x=?

x= (v^2 - u^2)/ 2a = 0.053

Height above bottom of window = 2 + 0.053 = 2.053 M
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njr008
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Report Thread starter 10 years ago
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Thank you!!!
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