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    i got 250...but not sure about the working;

    t (car) =(500-x)/30
    t( train B) = x/10

    t is the time they will both collide and x is the distance B is from the other side of the 500 mile distance.

    solved them to get x = 125m
    so train B has travelled 125m from one side...train A travelling the same speed would also have had to travel 125m from the other side.
    so the distance between them is 500- (125+125) = 250m
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    a method for people who haven't done relative distance...

    if the train and car travel at a ratio of speed of 1:3, then the train does 1/4 of the distance and the car, 3/4.
    so the car travels 125 miles, taking it 125/30 = 12.5 hrs.
    then, both trains do 125 miles in that time,
    so they're 250 miles apart.
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    (Original post by jazwalker)
    a method for people who haven't done relative distance...

    if the train and car travel at a ratio of speed of 1:3, then the train does 1/4 of the distance and the car, 3/4.
    so the car travels 125 miles, taking it 125/30 = 12.5 hrs.
    then, both trains do 125 miles in that time,
    so they're 250 miles apart.
    thanks for that
    didn't know how to work that out!!
    REP

    EDIT: Have to wait 11 more days. Have already repped you in the last 28 days.
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    guys how do you do these two:

    26 A budget airline operates a ‘sit anywhere’ policy on its short-haul flights.

    Flight NJ201 to Madrid is booked to capacity. In row 8, as in all the rows, there are six seats, three each side of the aisle:


    window 8A 8B 8C aisle 8E 8D 8F window


    Four passengers are already sitting in row 8: Maurice and Noola are in adjacent seats, but
    Noola refuses to sit by a window. Olive has chosen a window seat and Pete an aisle seat.
    This leaves two seats, and by the time Quentin and Ron arrive they are the only
    unoccupied seats on the plane.

    From this information, and if all the resulting seating arrangements are equally probable,
    what are the chances of Quentin and Ron finding two vacant seats next to each other?

    A 1/6
    B 1/4

    C 1/2

    D 2/3

    E 3/4





    27 A farmer has free range chickens. They are all over his farm and he has no easy way of
    counting them. However, he has devised a clever system. One day he rounded up 50
    chickens, put metal rings around their legs and let them go. The next day he rounded up
    50 chickens and found that 6 of them had rings on their legs.

    Assuming there was no change in the number of chickens between the two days, what was
    his estimate of the number of chickens on the farm? (Give your answer to the nearest
    whole chicken.)

    A 300

    B 367

    C 417

    D 1500

    E 2200
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    Anyone notice the Kaplan BMAT's analysis questions are too easy, and the science questions are just different?
    27 A farmer has free range chickens. They are all over his farm and he has no easy way of
    counting them. However, he has devised a clever system. One day he rounded up 50
    chickens, put metal rings around their legs and let them go. The next day he rounded up
    50 chickens and found that 6 of them had rings on their legs.

    Assuming there was no change in the number of chickens between the two days, what was
    his estimate of the number of chickens on the farm? (Give your answer to the nearest
    whole chicken.)

    A 300

    B 367

    C 417

    D 1500

    E 2200
    50/x=6/50

    x=50^2/6=416.someting....=417. C

    First one Is a little trickier. I get E, but I'm not sure.
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    Anyone want something similarly taxing, or does someone want to have a go at making up a chem/bio/physics question?

    I can give out strange and eluding maths questions, but my knowledge-bank of science questions is stunted.

    ok, a logic one *proud at having made it up*
    4 people are playing bridge, trying to work out who has the Jack (the King, Queen and Ace are also out). Only the one with the Jack is telling the truth.
    Who has the Jack?

    1: Either I, 2 or 4 have the King
    2: 1 has the king and 4 has the queen.
    4: Neither one nor 3 have the Jack
    4: I have the King and 3 has the Jack.
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    (Original post by jazwalker)
    ok, a logic one *proud at having made it up*
    4 people are playing bridge, trying to work out who has the Jack (the King, Queen and Ace are also out). Only the one with the Jack is telling the truth.
    Who has the Jack?

    1: Either I, 2 or 4 have the King
    2: 1 has the king and 4 has the queen.
    4: Neither one nor 3 have the Jack
    4: I have the King and 3 has the Jack.
    What's bridge? :p:
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    (Original post by Shayilalraya)
    guys how do you do these two:

    26 A budget airline operates a ‘sit anywhere’ policy on its short-haul flights.

    Flight NJ201 to Madrid is booked to capacity. In row 8, as in all the rows, there are six seats, three each side of the aisle:


    window 8A 8B 8C aisle 8E 8D 8F window


    Four passengers are already sitting in row 8: Maurice and Noola are in adjacent seats, but
    Noola refuses to sit by a window. Olive has chosen a window seat and Pete an aisle seat.
    This leaves two seats, and by the time Quentin and Ron arrive they are the only
    unoccupied seats on the plane.

    From this information, and if all the resulting seating arrangements are equally probable,
    what are the chances of Quentin and Ron finding two vacant seats next to each other?

    A 1/6
    B 1/4

    C 1/2

    D 2/3

    E 3/4
    C
    Reasoning (highlight to see)

    Here are the 2 possibilities, plotting just olive and pete, choosing the LH seat to be Olive (if she chooses 8F, just flip the diagram round):
    O_ P _ _ _ -1
    O _ _ P _ _ -2

    Now, in 1, when Noola and her partner sit, there are no 2 adjacent seats.
    In 2, when Noola and her partner sit, there are 2 adjacent seats.
    that gives 1/2
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    Try this one:

    A man wanted to get into his work building, but had forgotten his pin code.
    5 clues:

    - The fifth number plus the third equals 14
    - The fourth number is one more than the second number
    - The first number is one less than twice the second number
    - The second number plus the third number equals 10
    - The sum of all five numbers if 30.

    What was his pin code?
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    (Original post by Shayilalraya)
    27 A farmer has free range chickens. They are all over his farm and he has no easy way of
    counting them. However, he has devised a clever system. One day he rounded up 50
    chickens, put metal rings around their legs and let them go. The next day he rounded up
    50 chickens and found that 6 of them had rings on their legs.

    Assuming there was no change in the number of chickens between the two days, what was
    his estimate of the number of chickens on the farm? (Give your answer to the nearest
    whole chicken.)

    A 300

    B 367

    C 417

    D 1500

    E 2200
    So there are 50 chickens with rings and 6 were caught in a group of 50.
    The easiest way to do it then, is to look at how many chickens you'd have to catch, to catch all 50 ringed chickens.
    which is :
    (50/6)groups of 50 chickens
    or 2500/6
    =417
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    (Original post by Myoclonic Jerk)
    Try this one:

    A man wanted to get into his work building, but had forgotten his pin code.
    5 clues:

    - The fifth number plus the third equals 14
    - The fourth number is one more than the second number
    - The first number is one less than twice the second number
    - The second number plus the third number equals 10
    - The sum of all five numbers if 30.

    What was his pin code?
    74658
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    74658
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    :afraid:
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    (Original post by Myoclonic Jerk)
    Try this one:

    A man wanted to get into his work building, but had forgotten his pin code.
    5 clues:

    - The fifth number plus the third equals 14
    - The fourth number is one more than the second number
    - The first number is one less than twice the second number
    - The second number plus the third number equals 10
    - The sum of all five numbers if 30.

    What was his pin code?
    now thats hard!!
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    (Original post by Medicine Man)
    now thats hard!!
    It just looks hard. You can do it with algebra but it's harder than necessary. B is the simplest variable, just enter numbers from 1-9 for B, and see if it works. You'll notice 4 does.
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    Does anyone know the formula behind Question 7 of the Past Paper Section 2??
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    thanks ^^
    i'll do that
    so its pretty much trial and error to find what B could be and work from there?
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    (Original post by Isometrix)
    ANOTHER QUESTION:

    A train will randomly leave the station in City A at any time from 9am to 10am. The train will travel to City B at an average speed of 75 km/hour. If the distance from City A to City B is 425 km, what is the probability that the train will arrive at City B no later than 3:05pm?
    Hi, could someone please explain how they got 5/12 ?
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    (Original post by i_hate_examz)
    Hi, could someone please explain how they got 5/12 ?
    so the train takes 5hrs 40 mins
    so the train can arrive with equal probability any time between 2.40 and 3.40
    so let's divide it up into a total of 60 mins, of which 35 are after 3.05
    35/60 = 5/12
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    (Original post by PeeWeeDan)
    It just looks hard. You can do it with algebra but it's harder than necessary. B is the simplest variable, just enter numbers from 1-9 for B, and see if it works. You'll notice 4 does.
    basically all you do is make b equal all the letters, you should get

    a=2b-1
    c=10-b
    d=b+1
    e=b+4

    then u do a + c + d + e (all in terms of b) +b = 30
    then you get b, then you can get the other numbers

    code: 74658
 
 
 
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