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# C3 integration question watch

1. Prove that for values of the constant A such that A > 1.

I've got it up to but I don't know what else to do.
2. A^3-1 has a factor os A-1
3. Try factorising A^3 - 1 and see where dividing that by (A-1) gets you.
4. Uh... how is it factorized?
5. p^3 - q^3 = (p - q)(p^2 + pq + q^2) [This is a useful thing to remember]

Although to be fair, you could've worked it out for yourself.

let f(x) = x^3 - 1

let x = 1

f(1) = 0

Therefore (x - 1) is a factor

f(a) = x^3 - 1 = (x - 1)(Ax^2 + Bx + C)

Find A, B and C

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Updated: July 18, 2008
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