# Help Please! Cant do this Boolean Algebra problem, brain not good enough : (

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#1
Hi, would really appreciate it if someone could help me with this problem:

Show with boolean algebra that:

NotA . NotB XOR NotC . NotD = (A + B) XOR (C + D)

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1 year ago
#2
(Original post by Jaaames)
Hi, would really appreciate it if someone could help me with this problem:

Show with boolean algebra that:

NotA . NotB XOR NotC . NotD = (A + B) XOR (C + D)

De Morgan's gets you part of the way, then you need to use a property of XOR.
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#3
(Original post by RogerOxon)
De Morgan's gets you part of the way, then you need to use a property of XOR.
Cheers Roger,

I thought so, this is what I've got so far:

What do you mean by 'need to use a property of XOR'?

0
1 year ago
#4
First apply De Morgan's to each side of your XOR:

You should have something that differs from what you want by having a not on each side of the XOR. Look at the truth table for XOR to see the next step.
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#5
(Original post by RogerOxon)
First apply De Morgan's to each side of your XOR:

You should have something that differs from what you want by having a not on each side of the XOR. Look at the truth table for XOR to see the next step.
Thanks Roger,

After a bit of head scratching I managed to do it:
Thanks so much for your help though
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#6
(Original post by Jaaames)
Thanks Roger,

After a bit of head scratching I managed to do it:
Thanks so much for your help though
0
1 year ago
#7
(Original post by Jaaames)
Good. Here's how I would do it:

(Easiest to show this with a Karnaugh map)

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