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mechanics question rods with inextensible
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I have done part a and do not understand how to start part B. can somebody give me some hints. Thanks
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(Original post by mqb2766)
Take moments about A. Friction must balance the COM
Take moments about A. Friction must balance the COM
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#6
(Original post by dasda)
I have done part a and do not understand how to start part B. can somebody give me some hints. Thanks
I have done part a and do not understand how to start part B. can somebody give me some hints. Thanks
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(Original post by Muttley79)
Draw a force diagram showing forces at the wall. Now the system is in equilibrium so what can we do?
Draw a force diagram showing forces at the wall. Now the system is in equilibrium so what can we do?
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I have drawn a diagram. Is this correct.
(Original post by Muttley79)
Draw a force diagram showing forces at the wall. Now the system is in equilibrium so what can we do?
Draw a force diagram showing forces at the wall. Now the system is in equilibrium so what can we do?
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#9
(Original post by dasda)
Equate the vertical and horizontal forces to 0.
Equate the vertical and horizontal forces to 0.
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(Original post by Muttley79)
You could also take moments ...
You could also take moments ...
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(Original post by mqb2766)
The moments due to the center of mass and friction must balance.
The moments due to the center of mass and friction must balance.
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#13
(Original post by dasda)
For the force i got mg/2
For the force i got mg/2
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0.5mg=ur. but i dont know what R is.
(Original post by mqb2766)
so how does that relate to the coeff of friction?
so how does that relate to the coeff of friction?
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the answer is 5/12 and I don't see how I will get to that answer.
(Original post by mqb2766)
so how does that relate to the coeff of friction?
so how does that relate to the coeff of friction?
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#16
(Original post by dasda)
0.5mg=ur. but i dont know what R the is.
0.5mg=ur. but i dont know what R the is.
The horizontal part of the tension
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#19
(Original post by dasda)
but isn;t this in the direction of friction
but isn;t this in the direction of friction
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