I have this question:
I was able to successfully show the centre of mass of the uniform lamina is as stated.
For part (b) since both squares lie on the same line y=41/13 they must be spaced symmetrically from the centre of mass of the lamina for the centre of mass to remain constant (they have the same ‘mass’ - same area) so by symmetry I did this for part (c):
However the textbook answer states otherwise and the solution bank doesn’t provide any solution
I tried to recalculate the centre of mass by considering the uniform lamina as a particle at its original centre of mass and the two cut outs as negative masses:
This method also yielded the same result for a.
I don’t know where I’m going wrong because intuition tells me the two squares are cut down symmetrically from the original centre of mass so the centre of mass shouldn’t change...
Any help in clearing this misunderstanding would be appreciated, thanks in advance.