# SUVATWatch

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#1
The distance PS is 300m. The car passes P at 30m/s and remains at this speed for 2 seconds when it starts slowing down at a constant rate until S.

I am expected to make a speed-time graph for the car's motion from P to S. I first found the distance the car travelled for 2 seconds after crossing P which is 2 * 30 = 60. Therefore the remaining distance was 240m.
Using the SUVAT equation s = 0.5 (v + u)t, I found that that the time taken for the car to stop while decelerating was 16s. Therefore the total time is 18 seconds.
The next question, however, asks me to find the time taken to travel from P to S but I have already done that. Also, question 2 is worth 6 marks while 1 was 2 marks.
Was I wrong while drawing the graph? Can someone help me?
0
4 weeks ago
#2
(Original post by Mlopez14)
The distance PS is 300m. The car passes P at 30m/s and remains at this speed for 2 seconds when it starts slowing down at a constant rate until S.

I am expected to make a speed-time graph for the car's motion from P to S. I first found the distance the car travelled for 2 seconds after crossing P which is 2 * 30 = 60. Therefore the remaining distance was 240m.
Using the SUVAT equation s = 0.5 (v + u)t, I found that that the time taken for the car to stop while decelerating was 16s. Therefore the total time is 18 seconds.
The next question, however, asks me to find the time taken to travel from P to S but I have already done that. Also, question 2 is worth 6 marks while 1 was 2 marks.
Was I wrong while drawing the graph? Can someone help me?
I'm free to help, can you send me a pic of the question plz? The marks don't really make sense for what is needed. x
0
#3
0
4 weeks ago
#4
(Original post by Mlopez14)
Yeah I worked it through and you're completely right. The marks don't make sense to me. Maybe it's just an odd mark scheme or they got the part a and b marks the wrong way round? Although the graph is very easy? Just put lots of working for B
1
#5
(Original post by Jevans2208)
Yeah I worked it through and you're completely right. The marks don't make sense to me. Maybe it's just an odd mark scheme or they got the part a and b marks the wrong way round? Although the graph is very easy? Just put lots of working for B
thank you very much. Yes, that is an odd way to mark.
0
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