# AlgebraWatch

Announcements
Thread starter 4 weeks ago
#1
F(x)=|5-2x|+3 for 2<x<8. Find the range of the function F.
When I do this I get 4<f(x)<14 but the ans is 3<f(x)<14.
0
4 weeks ago
#2
(Original post by Shas72)
F(x)=|5-2x|+3 for 2<x<8. Find the range of the function F.
When I do this I get 4<f(x)<14 but the ans is 3<f(x)<14.
The minimum value of |5-2x| is 0 when x = 2.5. I would suggest you to draw the graph first, then determine the range.
1
Thread starter 4 weeks ago
#3
ok I will do that
0
4 weeks ago
#4
Cross Check the answer with ur teacher because I also had 4<f(x)>14
0
Thread starter 4 weeks ago
#5
ok sure which means there must be an error in the book
0
4 weeks ago
#6
(Original post by Shas72)
ok sure which means there must be an error in the
3<f(x)<14 is the correct answer. Have you drawn the graph?
0
Thread starter 4 weeks ago
#7
I did (2,4),(2.5,3) and (8,14)
0
Thread starter 4 weeks ago
#8
0
4 weeks ago
#9
(Original post by Shas72)
Do you see how the range is 3<f(x)<14 now?
0
Thread starter 4 weeks ago
#10
I still dont understand
0
Thread starter 4 weeks ago
#11
you mean 3 is the least you can get
0
Thread starter 4 weeks ago
#12
the vertex
0
4 weeks ago
#13
(Original post by Shas72)
you mean 3 is the least you can get
Yes indeed. The range of the function is the minimum value of f(x) up to the maximum value of f(x) for 2<x<8
0
Thread starter 4 weeks ago
#14
thanks a lot!
0
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• Bournemouth University
Wed, 19 Feb '20
• Buckinghamshire New University
Wed, 19 Feb '20
• University of Warwick
Thu, 20 Feb '20

### Poll

Join the discussion

Yes (166)
66.4%
No (84)
33.6%