ursbhhdb
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nvm
Last edited by ursbhhdb; 1 month ago
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Sir Cumference
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(Original post by ursbhhdb)
4x^2-31x+48 and x+y=k intersect once or twice, what is k
In other words, when you solve the equations simultaneously there must be at least 1 solution. Any thoughts on how to solve this?
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ursbhhdb
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(Original post by Sir Cumference)
In other words, when you solve the equations simultaneously there must be at least 1 solution. Any thoughts on how to solve this?
sub in y= k-x then find the discriminant
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RogerOxon
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(Original post by ursbhhdb)
4x^2-31x+48 and x+y=k intersect once or twice, what is k
You have:

y=4x^2-31x+48 and x+y=k

Is that any clearer?
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ursbhhdb
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so if y= k-x

k-x = 4x^2-31x+48
4x^2-31x+48= k

then would i find b^2-4ac???????
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Sir Cumference
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(Original post by ursbhhdb)
so if y= k-x

k-x = 4x^2-31x+48
4x^2-31x+48= k

then would i find b^2-4ac???????
You should put everything on one side of the equation first. Then you can use the discriminant.
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