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titration practical...help!!!
can some1 pleaze help me with my calculations......basically, this was the method of the titration we did....2.43g of Sulphamic acid was dissolved in water and made up to 250cm³ in a volumetric flask. The sodium hydroxide was then titrated against a 25.00cm³ portion (aliquote) of acid using Methyl Orange as indicator....i gt an average titre of 24.45cm³
i calculated the concentration of sulphamic acid...........2.43g/97 = 0.025051
therefore 250cm³ solution contains 0.02501 moles.
so 1000cm³ solution contains (0.02501/250) x 1000 = 0.1002 moles
Now i need to calculate the concentration of the sodium hydroxide....how do i do this???
NaOH + NH2SO3H = NH2SO3Na + H20
plz help me....
i calculated the concentration of sulphamic acid...........2.43g/97 = 0.025051
therefore 250cm³ solution contains 0.02501 moles.
so 1000cm³ solution contains (0.02501/250) x 1000 = 0.1002 moles
Now i need to calculate the concentration of the sodium hydroxide....how do i do this???
NaOH + NH2SO3H = NH2SO3Na + H20
plz help me....
Reply 1
Number of moles of acid in your 25cm3 aliquot =0.002501 (one tenth of that in the volumetric flask)
Therefore from equation number of moles alkali that react = 0.002501
So there are 0.002501 moles of alkali in 24.45cm3
so concentration = 0.002501/0.02445 = 0.102 mol/dm3
Therefore from equation number of moles alkali that react = 0.002501
So there are 0.002501 moles of alkali in 24.45cm3
so concentration = 0.002501/0.02445 = 0.102 mol/dm3
Reply 2
thanks 4 the reply....i ended up with the same answer, but my teacher said its wrong.....he said sumthin about 250cm3 instead of 25cm3......think he mite be wrong dunnoo....
Reply 3
11
oxymoron is right, with the figures you gave anyway. plus, if you want a check, think about it realistically, 25:24.45 is a near enough 1:1 ratio, so the concentrations will be to the same power of 10. slightly less NaOH than Sulphamic Acid means the NaOH concentration must be slighlty higher than the sulphamic acid...
so, not quite sure where your teacher is coming from when he says its wrong...
el stevo
n.b. just googled sulphamic acid and it says the formula is H_3NO_3S... maybe that could be where you are going wrong... where you get the formula from?
so, not quite sure where your teacher is coming from when he says its wrong...
el stevo
n.b. just googled sulphamic acid and it says the formula is H_3NO_3S... maybe that could be where you are going wrong... where you get the formula from?
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