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SHM

In (cii), the acceleration is taken as 9.81 ms-^2

Is it taken as 9.81 ms-^2 at each point throughout oscillation in all SHM cases involving vertical oscillations? Or just when the oscillating object is at maximum displacement? An explanation would be highly appreciated, really confused!
(edited 4 years ago)
assuming the mass of the box isn't affecting the oscillation...

The question is asking you for the amplitude at which the peak acceleration of the plate is equal to g - probably given in the data book as 9.8 or 9.81 ms^-2

general points about SHM are that the maximum size of the acceleration occurs at the greatest distance from the equilibrium position*... and it corresponds with the minimum speed... maximum speed occurs at the instant of passing through the equilibrium position where acceleration is zero.

* seems pretty reasonable when you remember that the restoring force is required to be proportional in size to the displacement from the equilibrium point... and F=ma
Reply 2
Original post by Joinedup
assuming the mass of the box isn't affecting the oscillation...

The question is asking you for the amplitude at which the peak acceleration of the plate is equal to g - probably given in the data book as 9.8 or 9.81 ms^-2

How do you deduce this by reading what the question states? Is understanding it connected with (ci)? Can you please explain that part too, since I don't understand it well. :frown:

Is a = g/9.81 ms-^2 at the extreme position (when x = amplitude) for oscillations always? Is it just a thing to remember?
Reply 3
Original post by cruduxcruo9
How do you deduce this by reading what the question states? Is understanding it connected with (ci)? Can you please explain that part too, since I don't understand it well. :frown:

Is a = g/9.81 ms-^2 at the extreme position (when x = amplitude) for oscillations always? Is it just a thing to remember?

"the cube loses contact momentarily with the plate".

Its basically the "vomit comet"
https://www.google.com/search?q=vomit+comet
When maximum acceleration of the plate is gravity (g), the cube begins to lose contact with the plate. When the plate is accelerating faster than gravity, the plate and the cube are moving independently and the cube appears to fly relative to the plate, as the acceleration of the cube is g.

For SHM, the maximum acceleration occrs at the extreme positions. When it is at the peak, loss of contact will ~occur when the acceleration is g.
Reply 4
Original post by mqb2766
"the cube loses contact momentarily with the plate".

Its basically the "vomit comet"
https://www.google.com/search?q=vomit+comet
When maximum acceleration of the plate is gravity (g), the cube begins to lose contact with the plate. When the plate is accelerating faster than gravity, the plate and the cube are moving independently and the cube appears to fly relative to the plate, as the acceleration of the cube is g.

For SHM, the maximum acceleration occrs at the extreme positions. When it is at the peak, loss of contact will ~occur when the acceleration is g.

I understand that for SHM max acceleration occurs at extreme positions. But, why is the maximum acceleration equal to 9.81 in this case? And how is the loss in contact related to the acceleration g?
Reply 5
The cube will want to accelerate at g. It is stopped by the plate as long as the acceleration of the plate is < g, hence they act in union. When the plate accelerates at just greater than g, the cube will lose contact with the plate as the cube will move under gravity, but the plate is accelerating away. With SHM, this will first occur at a peak.
(edited 4 years ago)

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