Logarithms and exponential functions

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Shas72
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#1
Report Thread starter 9 months ago
#1
Express 8 and o.25 as powers of 2 and hence simplify log base 5 (8) / log base5 (0.25).
I dont understand how to simplify
I get log base 5(2)^3/log base 5(2)^-2.
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Pangol
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#2
Report 9 months ago
#2
(Original post by Shas72)
Express 8 and o.25 as powers of 2 and hence simplify log base 5 (8) / log base5 (0.25).
I dont understand how to simplify
I get log base 5(2)^3/log base 5(2)^-2.
All good so far.

Do you know a different way of writing log_a (b^c) ?
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dxnixl
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#3
Report 9 months ago
#3
(Original post by Shas72)
Express 8 and o.25 as powers of 2 and hence simplify log base 5 (8) / log base5 (0.25).
I dont understand how to simplify
I get log base 5(2)^3/log base 5(2)^-2.
You’re doing well. Just follow this rule, and then cancel out everything other than the base  c for both the numerator and denominator!

 \log_ab^{c} = c \times log_ab
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Shas72
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#4
Report Thread starter 9 months ago
#4
which means 3 log base 5 (2) +2log base 5 (2) ?
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dxnixl
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#5
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#5
(Original post by Shas72)
which means 3 log base 5 (2) +2log base 5 (2) ?
Don’t you meant 3 log 5(2) / -2 log 5(2)?
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dxnixl
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#6
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(Original post by dxnixl)
Don’t you meant 3 log 5(2) / -2 log 5(2)?
After this just cancel out the ‘log 5(2)’ in both the numerator and denominator for the answer
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Shas72
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#7
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#7
yeah yeah sorry
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Shas72
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#8
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#8
so you cancel log base5 (2) and you get-3/2
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Shas72
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#9
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#9
thanks a lottttt
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