Linear interpolation help!!!

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#1
I don't get how to do linear interpolation to work out part d it's just not working
Last edited by Sidd1; 8 months ago
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8 months ago
#2
(Original post by Sidd1)
I don't get how to do linear interpolation to work out part d it's just not working
Is this question from one of the Edexcel textbooks?
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8 months ago
#3
(Original post by Sidd1)
I don't get how to do linear interpolation to work out part d it's just not working
What did you get for the mean and std dev and how did you try to do the linear interpolation?
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#4
(Original post by OL12345)
Is this question from one of the Edexcel textbooks?
Yeah from the AS Stats and Mechanics book
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#5
(Original post by mqb2766)
What did you get for the mean and std dev and how did you try to do the linear interpolation?
For the mean I got 23.4 and std dev: 7.32
I then added the mean and standard deviation and got 30.72 and then used linear interpolation but got 22.43?

I know it would be easier to show my working out but I can't at the moment
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8 months ago
#6
Er okay; calculate the maximum gust of wind within 1 std deviation and figure out which category it is in; once you have done that add another column to the table with cumulative frequency: plot a cumulative frequency graph and look for the segment line which represents your category: calculate the gradient of this line using the upper and lower bounds with the upper and lower frequencies; and then form an equation with your maximum gust of wind .within one standard deviation and x to denote its frequency: this will again be a gradient equation with 2 known x,y values and since you worked out the gradient of the line earlier you can solve the equation
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#7
(Original post by Levi.-)
Er okay; calculate the maximum gust of wind within 1 std deviation and figure out which category it is in; once you have done that add another column to the table with cumulative frequency: plot a cumulative frequency graph and look for the segment line which represents your category: calculate the gradient of this line using the upper and lower bounds with the upper and lower frequencies; and then form an equation with your maximum gust of wind .within one standard deviation and x to denote its frequency: this will again be a gradient equation with 2 known x,y values and since you worked out the gradient of the line earlier you can solve the equation
Ummmm this seems so longgg is there no other way without working out the gradient etc?
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8 months ago
#8
(Original post by Sidd1)
For the mean I got 23.4 and std dev: 7.32
I then added the mean and standard deviation and got 30.72 and then used linear interpolation but got 22.43?

I know it would be easier to show my working out but I can't at the moment
Obviously you want the mean +/- std dev so approximately 16 <-> 31. 16 lies in the 2nd interval and 31 in the last interval.
Just do the linear interpolation on each of these intervals. Not much working ...
Last edited by mqb2766; 8 months ago
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8 months ago
#9
https://www.physicsandmathstutor.com...hanics-year-1/

Worked answer will be on there
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#10
(Original post by OL12345)
https://www.physicsandmathstutor.com...hanics-year-1/

Worked answer will be on there
Yeah I had a look at that but I don't get it still
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8 months ago
#11
(Original post by Sidd1)
Ummmm this seems so longgg is there no other way without working out the gradient etc?
should only take about 3 mins; you only need to do the gradient of the specific category's line and you needn't plot the graph; there are other methods tho
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8 months ago
#12
(Original post by Sidd1)
Yeah I had a look at that but I don't get it still
How do you think you do linear interpolation for mean-stddev?
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#13
(Original post by mqb2766)
Obviously you want the mean +/- std dev so approximately 16 <-> 31. 16 lies in the 2nd interval and 31 in the last interval.
Just do the linear interpolation on each of these intervals. Not much working ...
Hang on, so the 16 and 31 represent the intervals and not the frequency? I thought they were the frequencies that's how I ended up with the wrong intervals. Right, okay makes sense thanks
Last edited by Sidd1; 8 months ago
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8 months ago
#14
(Original post by Sidd1)
Hang on, so the 16 and 31 represent the intervals and not the frequency? I thought they were the frequencies that's how I ended up with the wrong intervals. Right, okay makes sense thanks
mean and stddev must be the original varaible, not the frequency or probability.
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#15
(Original post by Levi.-)
should only take about 3 mins; you only need to do the gradient of the specific category's line and you needn't plot the graph; there are other methods tho
Oh okayyyy I prefer another method but thank you anywayy
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8 months ago
#16
(Original post by Sidd1)
Oh okayyyy I prefer another method but thank you anywayy
Yeah i was just doing this **** today and forgot all of my stats stuff so this was the method i found most useful
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#17
(Original post by mqb2766)
Obviously you want the mean +/- std dev so approximately 16 <-> 31. 16 lies in the 2nd interval and 31 in the last interval.
Just do the linear interpolation on each of these intervals. Not much working ...
Okay I worked it out I got 50.252 and then 6.3
But they subtracted them? Why is that?
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8 months ago
#18
(Original post by Sidd1)
Okay I worked it out I got 50.252 and then 6.3
But they subtracted them? Why is that?
They want the number of days its within the range, so the "width" of the frequencies.
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#19
(Original post by mqb2766)
They want the number of days its within the range, so the "width" of the frequencies.
oh okay thanks You're so good at Maths I wish I was someone who naturally kinda got it
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