Anonymous_4657
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I'm stuck on 9 part a. Unsure of what to do. Please may you help.Name:  Screenshot 2020-02-12 at 20.42.20.png
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mqb2766
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N is 1/3 of the way along the line. So do that for each of the x and y coordinates to get it.
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Anonymous_4657
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is N = 3,2

(Original post by mqb2766)
N is 1/3 of the way along the line. So do that for each of the x and y coordinates to get it.
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(Original post by mqb2766)
N is 1/3 of the way along the line. So do that for each of the x and y coordinates to get it.
Also I'm stuck on part b.
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(Original post by Anonymous_4657)
Also I'm stuck on part b.
You can calculate the magnitudes of each vector (pythagoras). Then show they correspond to a right angled triangle - they satisfy pythagoras.
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was my answer to part a correct?
(Original post by mqb2766)
You can calculate the magnitudes of each vector (pythagoras). Then show they correspond to a right angled triangle - they satisfy pythagoras.wa
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(Original post by Anonymous_4657)
was my answer to part a correct?
No, how did you get that. N is
ON = OP + 1/3(PQ)
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what's the answer?

(Original post by mqb2766)
No, how did you get that. N is
ON = OP + 1/3(PQ)
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(Original post by Anonymous_4657)
what's the answer?
I've given you the formula, please try and use it rather than asking for the numbers.
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(4,-6) ????
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(Original post by Anonymous_4657)
(4,-6) ????
Yes.
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(Original post by mqb2766)
Yes.
Thanks. I just didn't realise you had to start at the origin
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(Original post by Anonymous_4657)
Thanks. I just didn't realise you had to start at the origin
Generally things do.
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