# maths trig help!!!Watch

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Thread starter 1 week ago
#1
prove
cosecx-sinx = 1/secxtanx

is started with the lhs

I solved and I got to

cos^2x/sinx

I then separated this and got cosx/sinx x cosx = cotxcosx

what do I do next????
Last edited by Riannnne; 1 week ago
0
1 week ago
#2
(Original post by Riannnne)
prove
cosecx-sinx = 1/secxtanx

is started with the rhs

I solved and I got to

cos^2x/sinx

I then separated this and got cosx/sinx x cosx = cotxcosx

what do I do next????
I wouldn't start with the RHS if I were you. The LHS consists of two pieces - if you treat them as fractions and get them over the same denominator, you can combine them into one piecem which will be closer to where you are headed to.
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Thread starter 1 week ago
#3
(Original post by Pangol)
I wouldn't start with the RHS if I were you. The LHS consists of two pieces - if you treat them as fractions and get them over the same denominator, you can combine them into one piecem which will be closer to where you are headed to.
FML sorry for the typo I meant I started with the LHS.

the problem is I do not know how to get the answer
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1 week ago
#4
(Original post by Riannnne)
FML sorry for the typo I meant I started with the LHS.

the problem is I do not know how to get the answer
Oh yes, I can see what you did now!

You are so nearly there. You have got to cotx cosx. You need to get to 1/secxtanx, by which I assume you mean 1/(secx tanx). Let's write this as (1/sec x)(1/tan x). Now - what is 1/sec x? What is 1/tan x?
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