Muffins88
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#1
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Hi, I've been attempting to do this question for a while now and do not know what I am getting wrong. It wants me to find y'(-3) by implicit differentiation given ln(x^2−8y)=x−y+4 and y(-3)=1 and to also find the equation to the tangent line to the curve at the point (-3,1). Any help is greatly appreciated!
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AsemaM
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https://study.com/academy/answer/if-...-3-1-is-y.html
Hope this help.
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the bear
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they have got the wrong gradient at ( 3,1 )
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AsemaM
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#4
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(Original post by the bear)
they have got the wrong gradient at ( 3,1 )
They just have positive 3. The question is almost the same, just plug in (-3,1) in y' (so it is gonna be your gradient m ) and find the equation of the tangent using y-1 = m(x+3)
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the bear
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(Original post by AsemaM)
They just have positive 3. The question is almost the same, just plug in (-3,1) in y' (so it is gonna be your gradient m ) and find the equation of the tangent using y-1 = m(x+3)
ikr, but they did it wrong using positive 3
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AsemaM
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(Original post by the bear)
ikr, but they did it wrong using positive 3
What do you mean exactly? Maybe their question just had positive 3.
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the bear
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(Original post by AsemaM)
What do you mean exactly? Maybe their question just had positive 3.
they had the correct formula for y' but put in the numbers x = 3, y = 1 incorrectly
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the bear
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they should have got 5/7 instead of -5/9
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AsemaM
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#9
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(Original post by the bear)
they had the correct formula for y' but put in the numbers x = 3, y = 1 incorrectly
I see what you mean, but did you get your question correct?
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