Oakenari
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Hi everyone.

https://dynamicpapers.com/wp-content..._s10_qp_32.pdf

I'm struggling with question 4 (i) of this question. I have differentiated the equation given which y equals sinx/x. Now I'm a little stuck as to how to prove that the x-coordinate of M satisfies the equation x equals tanx. I would really appreciate some help here.

Thank you.

Oakenari
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Pangol
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(Original post by Oakenari)
Hi everyone.

https://dynamicpapers.com/wp-content..._s10_qp_32.pdf

I'm struggling with question 4 (i) of this question. I have differentiated the equation given which y equals sinx/x. Now I'm a little stuck as to how to prove that the x-coordinate of M satisfies the equation x equals tanx. I would really appreciate some help here.

Thank you.

Oakenari
That's the right approach. What is your dy/dx?
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Oakenari
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(Original post by Pangol)
That's the right approach. What is your dy/dx?
(xcosx - sinx)/x squared
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Pangol
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(Original post by Oakenari)
(xcosx - sinx)/x squared
OK, what next? M IS A minimum point, so what do you do with your dy/dx?
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Oakenari
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(Original post by Pangol)
OK, what next? M IS A minimum point, so what do you do with your dy/dx?
dy/dx is greater than the minimum point.
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RDKGames
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(Original post by Oakenari)
dy/dx is greater than the minimum point.
M is a min point so the gradient there is zero.
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