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Algebra

How u do question j? What do u do with -3 and -5? Do u +, -, ÷, ×?
Reply 1
Avatar for AWA00047
AWA00047
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10
IMG_20200225_193547.jpg
Rule of indices, you add powers when its multiplication, you subtract powers when its divide.
image.png
Reply 3
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AWA00047
OP
10
Can u just feel me do I +, -÷, × the -5 -3
Reply 4
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AWA00047
OP
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Please help me. I
So, you can use the second indice rule used in the picture to do question j.

So firstly, ignore the 7 and the 10, you'll add them back in later, when you do d^-3 divided by d^-5, you're doing -3 - -5, so it'll become d^2 on the top and you've gotten rid of the d on the bottom, then add the 7 and the 10 back in, so the final answer will be (7d^2)/10
Reply 6
Avatar for edbl01
edbl01
5
think of 7/10 and (d^-3)/(d^-5) separately

then [with the d bit] do (-3) - (-5) = 2

therefore the answer is 0.7 d^2
Reply 7
Avatar for AWA00047
AWA00047
OP
10
So you - them?
-3 - -5?
Reply 8
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AWA00047
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Oh. I get it. Thanks
Reply 9
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AWA00047
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Omg. Thanks
Reply 10
Avatar for DanKlim
DanKlim
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Original post by AWA00047
Oh. I get it. Thanks

Minus when you divide, add when you multiply.
Reply 11
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AWA00047
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15826233749566252977460886462525.jpgI need help with m. Don't get it
Original post by AWA00047
15826233749566252977460886462525.jpgI need help with m. Don't get it

Imagine there is a power of 1 there, so think of it as 3s^1 and then you can do it
Reply 13
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AWA00047
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Thanks

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