tahmidbro
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https://nhpapers.weebly.com/uploads/...e_20190605.pdf
Hi! I have a problem in question no. 22 b.
The mark scheme says that [ C2H5COOH] =[ C2H5COO-]
I dont know why. Any help with an explanationwould be highly appreciated :-)
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Pigster
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(Original post by tahmidbro)
https://nhpapers.weebly.com/uploads/...e_20190605.pdf
Hi! I have a problem in question no. 22 b.
The mark scheme says that [ C2H5COOH] =[ C2H5COO-]
I dont know why. Any help with an explanationwould be highly appreciated :-)
Imagine you had 1 mol of a weak acid, HA. If you add enough alkali to neutralise half of the acid (i.e. 0.5 mol reacts and 0.5 mol remains) then the 0.5 mol that reacts forms 0.5 mol of A-.

Since the two (HA and A-) are both dissolved in the same solution, i.e. their volume is the same, then since n(HA) = n(A-), then n/V = n/V, i.e. conc = conc.
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tahmidbro
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Thanks man!
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