# A-Level Maths: Pure Math 1 marker

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#1
The curve with equation y=x^(5/2) .lnx/4 where x>0 crosses the x-axis at the point P. Write the coordinates of P.

I can't seem to figure out the coordinates of this x intersect. It's only a 1 marker so it is quite frustrating...

All help is greatly appreciated
0
4 weeks ago
#2
(Original post by That_Guy_Omzz)
The curve with equation y=x^(5/2) .lnx/4 where x>0 crosses the x-axis at the point P. Write the coordinates of P.

I can't seem to figure out the coordinates of this x intersect. It's only a 1 marker so it is quite frustrating...

All help is greatly appreciated
Can you upload a picture of the question pls
Edit ahh misread the missing brackets in ln(x/4)?
Last edited by mqb2766; 4 weeks ago
0
4 weeks ago
#3
(Original post by That_Guy_Omzz)
The curve with equation y=x^(5/2) .lnx/4 where x>0 crosses the x-axis at the point P. Write the coordinates of P.

I can't seem to figure out the coordinates of this x intersect. It's only a 1 marker so it is quite frustrating...

All help is greatly appreciated
Why do you think that x=0 is not accepted as a valid solution? (Hint - recall your log knowledge).
In which case, what must make y=0?

Edit: Now that we have the original question, we can ignore my first sentence.
Last edited by dextrous63; 4 weeks ago
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#4
(Original post by mqb2766)
Can you upload a picture of the question pls
Edit ahh misread the missing brackets in ln(x/4)?
Here
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4 weeks ago
#5
(Original post by That_Guy_Omzz)
Here
So you have the product of two functions. One must be zero?
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#6
(Original post by dextrous63)
Why do you think that x=0 is not accepted as a valid solution? (Hint - recall your log knowledge).
In which case, what must make y=0?
Due to the asymptote at x=0?
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4 weeks ago
#7
(Original post by That_Guy_Omzz)
Due to the asymptote at x=0?
What is the domain (at A-level) of the ln function?
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4 weeks ago
#8
(Original post by That_Guy_Omzz)
Due to the asymptote at x=0?
Correct. However, since we now know x>0, as said in my edit, we can ignore considering x=0.

So, what must = 0?
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4 weeks ago
#9
Remember that ln(1)=0
Therefore how do I get ln 1?
4/4 is 1
Meaning x is 4
You can ignore the x to the power of 5/2 since anything multiplied by 0 is 0
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4 weeks ago
#10
(Original post by z4yn4)
Remember that ...
Hints not solutions pls.
See the sticky at the top of the forum
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#11
Thanks for the help everyone, I've got it
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