Is anybody able to help me answer this, I'm completely stuck! Thanks! Prove by contradiction that there are no positive integers a and b, with a odd, such that
Is anybody able to help me answer this, I'm completely stuck! Thanks! Prove by contradiction that there are no positive integers a and b, with a odd, such that
Is anybody able to help me answer this, I'm completely stuck! Thanks! Prove by contradiction that there are no positive integers a and b, with a odd, such that
a + 2b = Root8ab .
Suppose there there is a pair of integers (a,b), with a odd, such that
a+2b=8ab
Then (a+2b)2=8ab
Note that a+2b is (odd)+(even) hence it is (odd) and so the square (a+2b)^2 is odd ... but what's the problem ??
Is anybody able to help me answer this, I'm completely stuck! Thanks! Prove by contradiction that there are no positive integers a and b, with a odd, such that
Is anybody able to help me answer this, I'm completely stuck! Thanks! Prove by contradiction that there are no positive integers a and b, with a odd, such that
a + 2b = Root8ab .
By any chance do you remember what question paper this is from