Just want to check and see if I've done this right?
Question:
In a village, the ratio of males to females is 2:1.
40% of the people in the village are right-handed males.
25% of the village are right-handed females.
Show that the proportion of females who are right-handed is greater than the proportion of males who are right-handed.
I've done this by saying 3 parts=65% and 65% divided by 3 = 21.6(recurring)%.
Then 1x21.6(recurring)% = 21.6(recurring)%
2x21.6(recurring)% = 43.3(recuring)% so therefore, around 43% of the females in the village are right handed, while only round 23% of the males are right-handed.
I feel like I've probably done this wrong, as it's worth 6 marks and the working out I've done doesn't seem to be worth 6 marks aha.