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Maths ratio 6 marker help

Just want to check and see if I've done this right?

Question:
In a village, the ratio of males to females is 2:1.
40% of the people in the village are right-handed males.
25% of the village are right-handed females.
Show that the proportion of females who are right-handed is greater than the proportion of males who are right-handed.

I've done this by saying 3 parts=65% and 65% divided by 3 = 21.6(recurring)%.
Then 1x21.6(recurring)% = 21.6(recurring)%
2x21.6(recurring)% = 43.3(recuring)% so therefore, around 43% of the females in the village are right handed, while only round 23% of the males are right-handed.
I feel like I've probably done this wrong, as it's worth 6 marks and the working out I've done doesn't seem to be worth 6 marks aha.
It isn't 65% is 3 parts, it is 40% of the one part is RH males
and 25% of the two parts is RH females
Ratio of male:female =2:1
Therefore 200/3 % of village are males,100/3 % are females.

200/3 - 40 = 80/3 % are LH males
100/3 - 25 = 25/3% are LH females

40 %: 80/3 % =120:80 Rh males:Lh males

25%: 25/3% =75:25 Rh females:left hand females

Thus,120/80<75/25

1.5< 3

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