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#1
Can someone please explain how to work this question out. im really stuck.

A particle P of weight 20 N is suspended by two strings AP and BP. The tension in string AP is (ai + 8j ) and the tension in string BP is (6i+bj).

The value of a is _____ and the value of b is ____

The magnitude of the tension in string AP is ______

The angle that string BP makes with the vertical is _____

Give your answers as exact whole numbers or as decimals to 3 s.f.

ive already found b - 12
0
8 months ago
#2
For the first part:
Since the particle isn't moving, the horizontal forces equal to 0 and the vertical forces equal to zero.

You have already equalled the vertical forces to 0 to give b=12.
Now you just need to do this for the horizontal components. This will give you the value of a.

For the second part:
You can use Pythagoras to work this out.
If you draw a triangle with the horizontal and vertical forces on, the resultant will be the hypotenuse, so the magnitude is just the modulus of this. Does that make sense?

For the third part:
Again, draw a triangle. You can draw on the horizontal and vertical force of the tension in BP, and you know there is a right angle between the vertical and horizontal so you can use SOHCAHTOA (or the sine rule) to work out the angle.

Does this help?
Last edited by bfm.mcdermott; 8 months ago
1
8 months ago
#3
Is this integral maths? Lol I got really stuck on this one 😂😂😂
0
#4
thank

(Original post by bfm.mcdermott)
For the first part:
Since the particle isn't moving, the horizontal forces equal to 0 and the vertical forces equal to zero.

You have already equalled the vertical forces to 0 to give b=12.
Now you just need to do this for the horizontal components. This will give you the value of a.

For the second part:
You can use Pythagoras to work this out.
If you draw a triangle with the horizontal and vertical forces on, the resultant will be the hypotenuse, so the magnitude is just the modulus of this. Does that make sense?

For the third part:
Again, draw a triangle. You can draw on the horizontal and vertical force of the tension in BP, and you know there is a right angle between the vertical and horizontal so you can use SOHCAHTOA (or the sine rule) to work out the angle.

Does this help?
Hi
Thanks for this! It helped a lot
0
#5
(Original post by Himynameisdaisy)
Is this integral maths? Lol I got really stuck on this one 😂😂😂
Yh this is integral 😂😂
0
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