# Constant Acceleration Formulae

Watch
Announcements

Page 1 of 1

Go to first unread

Skip to page:

Could someone please help with this question? I'm really bad with this topic and just can't figure it out!

Particle moves in a straight line from A to B with constant acceleration. Particle moves from A with velocity 3ms^-1.

It reaches point B with velocity 5ms^-1 t seconds later.

One second after first particle leaves A, second particle also starts to move in a straight line from A to B with constant acceleration. Its velocity at poin A is 4ms^-1 and reaches B with velocity 8ms^-1 at the same time as first particle.

a)find the value of t

b)find the distance between A and B

Particle moves in a straight line from A to B with constant acceleration. Particle moves from A with velocity 3ms^-1.

It reaches point B with velocity 5ms^-1 t seconds later.

One second after first particle leaves A, second particle also starts to move in a straight line from A to B with constant acceleration. Its velocity at poin A is 4ms^-1 and reaches B with velocity 8ms^-1 at the same time as first particle.

a)find the value of t

b)find the distance between A and B

0

reply

Report

#2

(Original post by

Could someone please help with this question? I'm really bad with this topic and just can't figure it out!

Particle moves in a straight line from A to B with constant acceleration. Particle moves from A with velocity 3ms^-1.

It reaches point B with velocity 5ms^-1 t seconds later.

One second after first particle leaves A, second particle also starts to move in a straight line from A to B with constant acceleration. Its velocity at poin A is 4ms^-1 and reaches B with velocity 8ms^-1 at the same time as first particle.

a)find the value of t

b)find the distance between A and B

**JagodaRH**)Could someone please help with this question? I'm really bad with this topic and just can't figure it out!

Particle moves in a straight line from A to B with constant acceleration. Particle moves from A with velocity 3ms^-1.

It reaches point B with velocity 5ms^-1 t seconds later.

One second after first particle leaves A, second particle also starts to move in a straight line from A to B with constant acceleration. Its velocity at poin A is 4ms^-1 and reaches B with velocity 8ms^-1 at the same time as first particle.

a)find the value of t

b)find the distance between A and B

I'd start by laying out the information you know, s,u,v,a,t. for each particle - note some of the information for the first particle is linked to that of the second. In each case you know u,v. s is the same for each. And the times are linked. a's are unknown.

Since the distances are the same, you want to look to get an equation for s for the first particle and equate it to an equation for s for the second, and solve for t. Etc.

Have a go and post working if you get stuck.

0

reply

(Original post by

I'd start by laying out the information you know, s,u,v,a,t. for each particle - note some of the information for the first particle is linked to that of the second. In each case you know u,v. s is the same for each. And the times are linked. a's are unknown.

Since the distances are the same, you want to look to get an equation for s for the first particle and equate it to an equation for s for the second, and solve for t. Etc.

Have a go and post working if you get stuck.

**ghostwalker**)I'd start by laying out the information you know, s,u,v,a,t. for each particle - note some of the information for the first particle is linked to that of the second. In each case you know u,v. s is the same for each. And the times are linked. a's are unknown.

Since the distances are the same, you want to look to get an equation for s for the first particle and equate it to an equation for s for the second, and solve for t. Etc.

Have a go and post working if you get stuck.

0

reply

Report

#4

(Original post by

okay thank you so much for the help! But why is u and v the same for each particle if the question states different velocities?

**JagodaRH**)okay thank you so much for the help! But why is u and v the same for each particle if the question states different velocities?

In each case you know u,v.

s is the same for each.

And the times are linked.

a's are unknown.

0

reply

(Original post by

They're not, it's clearer if I put the two sentences on different lines. The lowercase "s" makes it look as if the sentence continues when it doesn't.

In each case you know u,v.

s is the same for each.

And the times are linked.

a's are unknown.

**ghostwalker**)They're not, it's clearer if I put the two sentences on different lines. The lowercase "s" makes it look as if the sentence continues when it doesn't.

In each case you know u,v.

s is the same for each.

And the times are linked.

a's are unknown.

0

reply

X

Page 1 of 1

Go to first unread

Skip to page:

### Quick Reply

Back

to top

to top