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ADEBE294-2CD0-46DE-B2A0-6AE72474040B.jpg.jpeg got one mark for this, I assumed that I would have to find the area of a sector however it doesn’t equal to 460 as given
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mqb2766
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Original post by Cody0101
ADEBE294-2CD0-46DE-B2A0-6AE72474040B.jpg.jpeg got one mark for this, I assumed that I would have to find the area of a sector however it doesn’t equal to 460 as given

Upload your sector calculation pls.
Reply 2
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Cody0101
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Original post by mqb2766
Upload your sector calculation pls.


I did 105/360xpix23.0867
Reply 3
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mqb2766
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Original post by Cody0101
I did 105/360xpix23.0867

How do you get 23?
Use the cos rule on the triangle to get the third length (the radius)
(edited 4 years ago)
Reply 4
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Cody0101
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Original post by mqb2766
How do you get 23?
Use the cos rule on the triangle to get the third length (the radius)


So I did 14^2+27^2-2x27x14sin32=524.3810
Square root to get 22.8993 I’m unsure of what to do next
Reply 5
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mqb2766
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Original post by Cody0101
So I did 14^2+27^2-2x27x14sin32=524.3810
Square root to get 22.8993 I’m unsure of what to do next

It's called the cos() rule for a very good reason ....
Also it's r^2 in the circle area or sector area. You don't have to root the first calculation.
(edited 4 years ago)
Reply 6
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mqb2766
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Original post by E.R.Cross
I would use the cosine rule to
Hope this helps :smile:

Pls delete - hints not solutions. See the forum sticky.
Reply 7
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Cody0101
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i get it now thank you

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