# Working out acceleration from velocity and distance (maths)

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I know i need to use the formula f=ma but i dont know how to gt acceleration, with these two all i know is acceleration=velocity\time

I'll post the question below.

Appreciate any help

I'll post the question below.

Appreciate any help

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#3

so you can use the equation: v^2 = u^2 + 2as

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#6

(Original post by

well id hate to ask but I'm stuck on 7ii as well

**A0W0N**)well id hate to ask but I'm stuck on 7ii as well

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so does that mean the acceleration will always be the same o for the iii) i could sub 10 in and then find the force required, if thats correct i think i understand these questions now

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#8

(Original post by

so does that mean the acceleration will always be the same o for the iii) i could sub 10 in and then find the force required, if thats correct i think i understand these questions now

**A0W0N**)so does that mean the acceleration will always be the same o for the iii) i could sub 10 in and then find the force required, if thats correct i think i understand these questions now

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#10

you can not use f=ma or any suvat equations here because there is no acceleration

if a=0 then the force he exerts is same as the resistance force both forces cancel out and acceleration is 0. so i guess the force he exerts must be same as the resistance force you found in i.

if a=0 then the force he exerts is same as the resistance force both forces cancel out and acceleration is 0. so i guess the force he exerts must be same as the resistance force you found in i.

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(Original post by

you can not use f=ma or any suvat equations here because there is no acceleration

if a=0 then the force he exerts is same as the resistance force both forces cancel out and acceleration is 0. so i guess the force he exerts must be same as the resistance force you found in i.

**papie**)you can not use f=ma or any suvat equations here because there is no acceleration

if a=0 then the force he exerts is same as the resistance force both forces cancel out and acceleration is 0. so i guess the force he exerts must be same as the resistance force you found in i.

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#12

Note also for part iii), use Newton's First Law since the (horizontal) velocity is constant, the sum (horizontal) net force is zero so the force applied must equal the magnitude of the frictional force.

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#13

(Original post by

but the acceleration in part i was -0.2 so how can it be the same here if acceleration is zero; because he's at a constant speed?

**A0W0N**)but the acceleration in part i was -0.2 so how can it be the same here if acceleration is zero; because he's at a constant speed?

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