# physics help

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#1
A 45.0 kg child jumps on a 5.00 kg pogo stick with spring constant 3650 N/m. Ignoring damping effects, find the frequency of the child’s motion.

Now, im a little bit confused. in the earlier part of the question it asked me to work out the angular frequency and i used F= 1/2pie (squareroot(k/m) and got 1.83 but for this one I dont now which is the linear formula and which one to apply
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9 months ago
#2
The formula for the angular frequency of a mass on a spring is ω = √(k/m)
The frequency, f, (in Hertz) is given by ω/2π
which is
f = (1/2π)√(k/m
Last edited by Stonebridge; 9 months ago
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#3
(Original post by Stonebridge)
The formula for the angular frequency of a mass on a spring is ω = √(k/m)
The frequency, f, (in Hertz) is given by ω/2π
which is
f = (1/2π)√(k/m
so which formula do I need to use to work out the frequency as i have already used this formula for angular frequency.
0
9 months ago
#4
You use the formula I gave you for frequency, f.
If you used that for angular frequency, you used the incorrect formula.
The formula for that is also given in my answer.
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#5
(Original post by Stonebridge)
You use the formula I gave you for frequency, f.
If you used that for angular frequency, you used the incorrect formula.
The formula for that is also given in my answer.
that gives me wrong answer for angular frequency.
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9 months ago
#6
In which case we need to see the complete original question (if there is any other part or data you haven't given here), and your working, to try to find out what has happened. Sometimes the given answers can be wrong.
I calculate, from the values you have given here, and using the equations given,
angular frequency ω = √(3650/50) = 8.54 rads-1
frequency f = ω/2π = 8.54/2π = 1.36 Hz

How did you get 1.83?
0
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