The Student Room Group

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(edited 4 years ago)
Reply 1
Original post by ottersandseals1
A solid formed by rotating the curve y = x^2 +4 between x =1 and x =t, t>1, through 360 degrees about y-axis. Find the value of t for the volume of solid formed is 40pi

Where have I gone wrong?
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Haven't checked the whole thing so it could be elsewhere, but it may be your limits of integration. You correctly have an upper limit of t2 + 4, which is what y comes to when x = t. But what about when x = 1, the lower limit?
Reply 2
Original post by ottersandseals1
Yeah I forgot to put that in
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Has that given you the right answer? You'll understand that I'm not inclined to check every line unless you're still having problems.
Original post by Pangol
Has that given you the right answer? You'll understand that I'm not inclined to check every line unless you're still having problems.

I don't know what the answer is
Reply 4
Original post by ottersandseals1
I don't know what the answer is

In that case, how did you know you weren't right the first time?!

Just had a closer look at your working. It doesn't appear that you have actually done any integration.
Reply 5
Original post by ottersandseals1
I don't know what the answer is

Just checked the answer - you will know you probably have it right if it comes out as an integer.
Reply 6
Original post by ottersandseals1
is it 2.5?

Not what I got (and not an integer!). Quite possible I made a slip, I grant you.

But do you see what I mean about you now having actually integrated?

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