The Student Room Group

Integration

the current i, in amps, that flows in a circuit is given by,
i= 4(1+e -0.1t) square root
find the total charge q that has flowed through the circuit between times t=1s and t=2s
NB: the charge q coulumbs flowing through a circuit is given by q= I dt
Reply 1
Original post by raffay13
the current i, in amps, that flows in a circuit is given by,
i= 4(1+e -0.1t) square root
find the total charge q that has flowed through the circuit between times t=1s and t=2s
NB: the charge q coulumbs flowing through a circuit is given by q= I dt

Can you upload a picture of the question? Is the current
I = sqrt(4(1+exp(-0.1t)))
or ....
What have you tried so far? Trying some substitutions is a good place to start.
(edited 4 years ago)
Reply 2
i havent tried it yet but this is what the question looks like>>>>>IMG_3809.jpg
Original post by raffay13
i havent tried it yet but this is what the question looks like>>>>>IMG_3809.jpg


This is just normal definite integration without the use of any special technique. You can split the current into 2 parts - constant part and varying with respect time part

abconstantdt=[constant×t]ab \int^b_a \text{constant} dt = [\text{constant} \times t ]^b_a

abentdt=[(1/n)ent]ab \int^b_a e^{nt} dt = [(1/n) e^{nt}]^b_a
Reply 4
Original post by Eimmanuel
This is just normal definite integration without the use of any special technique. You can split the current into 2 parts - constant part and varying with respect time part

abconstantdt=[constant×t]ab \int^b_a \text{constant} dt = [\text{constant} \times t ]^b_a

abentdt=[(1/n)ent]ab \int^b_a e^{nt} dt = [(1/n) e^{nt}]^b_a


Agreed. Where is the sqrt mentioned in the original post - not a question for you.

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