maths probability questionWatch
In a sixth form of 234 students, 108 study English, 52 study History, and 25 study both English and History.
A student is selected at random. Find the probability that the student studies neither English nor History.
Give your answer to 3 s.f.
This is what the Venn diagram should look like, let me know if it’s wrong or you need help
First draw a venn diagram to make it easier for you
Those who studies BOTH =25
Those who studies English ONLY= 108 - 25 = 83
Those who studies History ONLY = 52 - 25 = 27
Those who studies NEITHER = 234 - ( 25 + 83 + 27 ) = 99
( want to check add 25 + 83 + 27 + 99 = 234 )
so P( Neither subjects ) = 99 / 234 = 0.423 3 s.f
So thats all !
Check the answer please , haven't done Statistics in a while 😅😅
Check this link it will help you too in that type of question https://www.coursehero.com/file/4051...robabilitydoc/
Hope I helped and Good luck !!