# maths probability question

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#1
Hi, can someone help me with this question please?

In a sixth form of 234 students, 108 study English, 52 study History, and 25 study both English and History.

A student is selected at random. Find the probability that the student studies neither English nor History.

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9 months ago
#2

This is what the Venn diagram should look like, let me know if it’s wrong or you need help
Last edited by adzz.s1; 9 months ago
0
9 months ago
#3
Hey, so I tried this one , check here
First draw a venn diagram to make it easier for you
Those who studies BOTH =25
Those who studies English ONLY= 108 - 25 = 83
Those who studies History ONLY = 52 - 25 = 27
Those who studies NEITHER = 234 - ( 25 + 83 + 27 ) = 99
( want to check add 25 + 83 + 27 + 99 = 234 )

so P( Neither subjects ) = 99 / 234 = 0.423 3 s.f

So thats all !
Check the answer please , haven't done Statistics in a while 😅😅

Hope I helped and Good luck !!
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#4
Thanks guys!! this helped a lot it's correct by the way
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